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Does anyone know if the adiabatic equation applies to aluminium conductors when calculating the csa of earthing conductors, or guide me to where I might be able to find an answer.
Cheers
 
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telectrix

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what do you call a supply circuit? if it's a distribution circuit, 5 secs. max. applies, but the time/current graphs will give you the actual diss. time .
 
what do you call a supply circuit? if it's a distribution circuit, 5 secs. max. applies, but the time/current graphs will give you the actual diss. time .
Sorry it's a building with a block of flats the flats are fed from meters located in a communal hall with each flat fed from the bemco, I've never really understood why a shorter disconnection time requires a smaller earthing conductor, as It stands with a 5 second disconnection time min earth would be 18mm but with 0.4 disconnection time it drops to 5mm
 

telectrix

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yeah, but those figures are the max. allowable diss. time, not the actual time which you get from the time/current graphs.
 

Strima

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Sorry it's a building with a block of flats the flats are fed from meters located in a communal hall with each flat fed from the bemco, I've never really understood why a shorter disconnection time requires a smaller earthing conductor, as It stands with a 5 second disconnection time min earth would be 18mm but with 0.4 disconnection time it drops to 5mm
Because the fault clears quicker and the conductor will not get to a high enough temperature to melt, if it was 5 seconds there's plenty of cooking time.
 

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