A
arturas
Hi there guys, just to be sure I wanted to double check with someone more experienced. Usually all my work is re-wiring of properties. Now I need to feed up the top flat. The run will be roughly 45-50 meters, with a 60a fuse.
Now when calculating the voltage drop, as there will be lighting circuits it has to be 3%. I'm thinking of 25mm three core swa. It will be run on the tray next to other cables feeding other flats. And when calculating the voltage drop I'm using column z of a table 4d4b which is 1.75 per amper per meter: 1.75x60x50/1000= 5.25 which is < then 3% of 230v. And now when trying to determine a cable size I'm using a formula: In/CgCaCsCdCiCfCc . Because it's above the ground in free space no thermal insulation and the ref method is e, all of the factors =1 except the grouping factors which is 0.72. In that case I get 60/0.73= 83 which is less then maximum current carrying capacity of 25mm cable. Am I right?thanks for any help!
Now when calculating the voltage drop, as there will be lighting circuits it has to be 3%. I'm thinking of 25mm three core swa. It will be run on the tray next to other cables feeding other flats. And when calculating the voltage drop I'm using column z of a table 4d4b which is 1.75 per amper per meter: 1.75x60x50/1000= 5.25 which is < then 3% of 230v. And now when trying to determine a cable size I'm using a formula: In/CgCaCsCdCiCfCc . Because it's above the ground in free space no thermal insulation and the ref method is e, all of the factors =1 except the grouping factors which is 0.72. In that case I get 60/0.73= 83 which is less then maximum current carrying capacity of 25mm cable. Am I right?thanks for any help!