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Lee7534

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New to the forum so hi everyone.
I'm due to start an electrician course in July so I thought I'd revise some maths as it's been some years since I've done any. I bought the book 'Electrical installation calculations'. I've flown through resistors in series and parallel so far but have come up against a brick wall with the following question. Any help with solving it and showing step by step workings would be massively appreciated. As follows:

To vary the speed of a d.c. series motor it is usual to connect a diverter resistor in parallel with the field winding. The field of a series motor has a resistance of 0.6Ω and the diverter resistor has three steps, of 5Ω, 4Ω and 2Ω. Assuming that the total current is fixed at 28A, find out how much current flows through the field winding at each step of the diverter.

Many thanks
Lee
 

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Lee7534

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