P
pprendeville
I’ve got a few queries about the operation of the 3-step control circuit. Have an exam on it this week and would like to clarify a few points as we’ll be asked a few questions on it. I’ll give an explanation of what the circuit demonstrates first.
We want to maintain a constant pressure in a system. In this case, we want a constant pressure of 3 bar, this is set-point 1. To achieve this we are using an ON/OFF controller made by Festo and a pressure sensor. We use a hysteresis of 0.4 and finally we’ve got a 2nd setpoint of 3.5 bar which is like a high pressure limit. If pressure goes above this value, the reservoir will have to exhaust. 1V corresponds to 1 bar of pressure so to get three bar, we need to set S A1 (which you can see in the picture where the selector switch is to) to 3V and S A2 to 3.5V. H A1 is set to 0.4V and there is no hysteresis for the second setpoint, 3.5V.
So that’s they’re the setup values that need to be entered. Next up is the pneumatic circuit. I understand the principles of operation of the pneumatic circuit and can set it up fine. It’s the electrical circuit that I’m getting stuck on. The contacts on relay KA1 are NC. When the reservoir reaches 3 bar pressure, i.e. the pressure sensor sends a 3V signal, the NC contacts of KA1 open and solenoid Y1 deenergises. On the pneumatic circuit this sends the 5/3 way valve back to the mid position. So this is where I get a bit stuck. When KA1 is deenergised, does the contact of KA1 that’s wired in series with solenoid Y2 open also. I think this is an electrical interlock so both Y1 and Y2 can’t operate at the same time. If the pressure goes to 2.79 bar, Y1 will be energised again to top up the reservoir. Will fill it to 3.21 bar (taking into account hysteresis of 0.4V).
Perhaps someone can just clarify the interlocking technique for this particular circuit and I should be good to go then.
We want to maintain a constant pressure in a system. In this case, we want a constant pressure of 3 bar, this is set-point 1. To achieve this we are using an ON/OFF controller made by Festo and a pressure sensor. We use a hysteresis of 0.4 and finally we’ve got a 2nd setpoint of 3.5 bar which is like a high pressure limit. If pressure goes above this value, the reservoir will have to exhaust. 1V corresponds to 1 bar of pressure so to get three bar, we need to set S A1 (which you can see in the picture where the selector switch is to) to 3V and S A2 to 3.5V. H A1 is set to 0.4V and there is no hysteresis for the second setpoint, 3.5V.
So that’s they’re the setup values that need to be entered. Next up is the pneumatic circuit. I understand the principles of operation of the pneumatic circuit and can set it up fine. It’s the electrical circuit that I’m getting stuck on. The contacts on relay KA1 are NC. When the reservoir reaches 3 bar pressure, i.e. the pressure sensor sends a 3V signal, the NC contacts of KA1 open and solenoid Y1 deenergises. On the pneumatic circuit this sends the 5/3 way valve back to the mid position. So this is where I get a bit stuck. When KA1 is deenergised, does the contact of KA1 that’s wired in series with solenoid Y2 open also. I think this is an electrical interlock so both Y1 and Y2 can’t operate at the same time. If the pressure goes to 2.79 bar, Y1 will be energised again to top up the reservoir. Will fill it to 3.21 bar (taking into account hysteresis of 0.4V).
Perhaps someone can just clarify the interlocking technique for this particular circuit and I should be good to go then.