C
claret73
Something I haven't really done, so am I correct with the Maths? Just looking to reduce costs & use 2 core against 3.
Found the Table from the Sticky. Anyhow 10mm SWA is labelled Red & the footnote states the Armoured would not satisfy as the CPC (but maybe by Calculation). So...
2 Core SWA 90deg XLPE, 55m Run Approx
Using the K Values in the above 'Sticky Table' to find Copper equivalent:
K2/K1xS
46/143x10mm=3.2mmsq (K2 being SWA, K1 Factor for 10mm Line in 2 Core SWA x 10mm Line conductor)
Is this right? Regs is K1/K2xS
Ze TNS=0.8 (Not measured using default for calcs)
R1= 1.83
R2= 6.0 (Found from a Link to a Table for resistance of SWA)
Zs= Ze+ (R1+R2)
Zs= 0.8 =(1.83/1000x55mx1.28 + 6.0/1000x55m)
ZS= 0.8 + (0.12+0.33)
ZS= 1.25ohms
Fault Current = 230/1.25=184A
Log Log disconnects 0.1s
Adiabatic:
S=Sqrt (184sqx0.1)/46 = 1.26mmsq
So as this is less than the K Factor calc for the armoured I can use the Armoured as CPC??? Think I need a Vorderman...& is there an less longwinded way to find this out?
Found the Table from the Sticky. Anyhow 10mm SWA is labelled Red & the footnote states the Armoured would not satisfy as the CPC (but maybe by Calculation). So...
2 Core SWA 90deg XLPE, 55m Run Approx
Using the K Values in the above 'Sticky Table' to find Copper equivalent:
K2/K1xS
46/143x10mm=3.2mmsq (K2 being SWA, K1 Factor for 10mm Line in 2 Core SWA x 10mm Line conductor)
Is this right? Regs is K1/K2xS
Ze TNS=0.8 (Not measured using default for calcs)
R1= 1.83
R2= 6.0 (Found from a Link to a Table for resistance of SWA)
Zs= Ze+ (R1+R2)
Zs= 0.8 =(1.83/1000x55mx1.28 + 6.0/1000x55m)
ZS= 0.8 + (0.12+0.33)
ZS= 1.25ohms
Fault Current = 230/1.25=184A
Log Log disconnects 0.1s
Adiabatic:
S=Sqrt (184sqx0.1)/46 = 1.26mmsq
So as this is less than the K Factor calc for the armoured I can use the Armoured as CPC??? Think I need a Vorderman...& is there an less longwinded way to find this out?