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T

turbomen

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A transistor is set up in a test circuit and a base current of 12μA is measured. At the same time, the collector current is measured and found to be 2.28mA. The current gain for the transistor under these conditions would be:

(A) 9
(B) 19
(C) 190
(D) 1900
(E) None of the above values


Could you tell me how can I get the answer?
 
G

Guest123

  • Thread Starter Thread Starter
  • #2
Proper head scratching stuff this matey.

I THINK the sum is current out/current in = 0.0228/0.000012 which gives the answer of 1900. So (D).
 
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P

pushrod

  • Thread Starter Thread Starter
  • #3
Proper head scratching stuff this matey.

I THINK the sum is current out/current in = 0.0228/0.000012 which gives the answer of 1900. So (D).

think your mA conversion is out - try 0.00288A ... so not D unless i am missing something :)
 
G

Guest123

  • Thread Starter Thread Starter
  • #4
Fair play.

I changed my mind once already because of the decimal point.

To clarify then - 2.28milliamp = 0.00228amp (divide by 1000).

12microamp = 0.000012amp (divide by 1000,000).

So the answer would be 0.00228/0.000012 = 190. = (C)

I think:eek:.
 
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