Urgent knoledge needed

[lofty84]

Can anyone help me out here I'm doing my 204 and it's asked me to explain why the supply current is reduced when the capacitor is in the circuit

It also says when the choke voltage is added to the lamp voltage why does it not equal the supply voltage

I've got about 5 lines to fill

any chance of someone helping me out here

 

[kmatthews]

connecting a voltage to the
plates of a capacitor causes it to charge up to the potential of the supply.
This involves electrons moving around the circuit to create the necessary
charge conditions and, therefore, this action does not occur instantly, but
takes some time, depending upon the size of the capacitor and the resistance
of the circuit. Such circuits are called capacitor–resistor (CR) circuits,
and have many applications in electronics as timers and triggers and for
controlling the time base sweeps of a cathode ray oscilloscope.

Most installations have a low or bad power factor because of the inductive
nature of the load. A capacitor has the opposite effect of an inductor, and
so it seems reasonable to add a capacitor to a load which is known to have
a lower power factor.