Discuss What is the equivalent resistance of this network in the Electrical Courses and Electrical NVQ's area at ElectriciansForums.net

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turbomen

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Two resistors, R1 and R2 are connected in parallel. R1 is 2kW, R2 is 4kW. What is the equivalent resistance of this network (answer rounded to nearest whole Ohm):

Could you tell me how can you get the answer?
 
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andyb

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turbomen

Are you trying to get us to do your homework?

1/r=1/r1+1/r2

you do the calculations
 
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turbomen

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  • #3
Hi Andy,

Thank you for your help but it is not a homework - it is a test review question.

Cheers,
 
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turbomen

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  • #5
Can I do in this way:-

1/r = 1/2k+1/4k

1/r = 2/4k+1/4k

1/r= 3/4k

r=1333


But could you mind tell me about the formula? Because I do not learn the formula in before.


Cheers,
 

andyb

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You put the decimal point in the wrong place, the answer is 1.33 but you got it.

The formula is the method for calculating resistance in parallel, I don't know what else to say.
 
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turbomen

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  • #7
Hi Andy,

Thank you for your kind reply. But it is a multi-ple choice question: The only choices are 60, 13, 6000 or 13330.
 

andyb

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Sorry turbomen.I missed the K value and worked it out as 2 & 4 ohms.

So yes, you calculated it correctly.
 

old dog

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1/requv = 1/R1 + 1/R2

requiv = !/R1 + R2
 
G

Guest123

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  • #10
And for a series circuit = R1+R2+R3 etcetc.
 
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