B

bobbydoran16

not to sure on how to find the wats for the power cable calcs could anyone help me its for a ring with 3 Dubble sockets on
DB05-3L2
cable size: 2.5mm
temperature rating:90°c
total demand
32a
29.125m
Design current
w/230
lb= 0.547A
Ambient factors
1 cable
Ca=0.91
Cg=1.0
It=design current/ambient factors
10a/(0.91x1.0)=10.989
It=10.989
cable current carrying capacity
IZ= 24a
Volt drop
VD=mvamxibxl/1000
()/1000) =
Vdx1000/mv/a/ib ans x4 =L
Max permitted disconnection time
Ze= 0.11+/1000 =0.Ω
Zs =0 Ω
earth fault loop impedance
if= / =
 
Is this a college question? Or an extremely over thought real life situation?
 
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If you want help with calculations, please post in a clear, correctly formatted manner with your working and specific notes as to where you are stuck, and we will help you. In maths and engineering, you must be precise - e.g. lower and upper case letters have different meanings and you must use the correct ones with the correct symbols and formatting. I cannot be bothered to decipher word salad like:

mvamxibxl
or
0.11+/1000 =0.Ω
Sorry if that sounds unhelpful but you must help us to help you, or you won't learn anything from the answers.
 
If you want help with calculations, please post in a clear, correctly formatted manner with your working and specific notes as to where you are stuck, and we will help you. In maths and engineering, you must be precise - e.g. lower and upper case letters have different meanings and you must use the correct ones with the correct symbols and formatting. I cannot be bothered to decipher word salad like:


or

Sorry if that sounds unhelpful but you must help us to help you, or you won't learn anything from the answers.
hi yes sorry its just cos i copyed and pasted it from the one above as that was for the lighting
 

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help on cable calcs power
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