2391 written exam last nite

[scotsparky]

aaaaa that wasnt said only saw a resistive value.

be carefull when doing larger sizes as you have to decide if its a resistive, inductive or reactive load.

 

[GStueyXR]

What pi55es me off most, is that it is a requirement that we carry BS7671 and OSG, so why not give us the info out of em ???

 

[Charles West]

I doubled the length of the conductors, but now I'm confused:

Table 4D1B in Appendix 4 states that 10mm sq cable in conduit drops 4.4mV/A/m at 70 [FONT=Tahoma, sans-serif]°[/FONT]C
The title at the top states:[FONT=Tahoma, sans-serif] 'Single-core ... cables', [/FONT]so I'd assume the values are for one conductor only.

The table in the question paper is different. 'Figure 1 below shows information on the resistance of conductors in mΩ/A/m.'[FONT=Tahoma, sans-serif]
The bottom row says nothing more than: 1m of a 10mm² conductor has a resistance of 1.83m[/FONT]Ω at 20[FONT=Tahoma, sans-serif]°C.
At 1amp, this gives a voltage drop of 1.83mV.
The scenario also mentions single cables in trunking and conduit.

Sadly, when I compare the figures with BS7671, logic and common-sense cease to apply.
The values on the exam paper should be the same as the values listed in BS7671, table 4D1B, but reduced a certain amount because they're at [/FONT]20[FONT=Tahoma, sans-serif]°C[/FONT][FONT=Tahoma, sans-serif] instead of 70.

BS7671 says a 1m length of 10mm [/FONT][FONT=Tahoma, sans-serif]²[/FONT][FONT=Tahoma, sans-serif] cable drops 4.4V per amp,
C&G say that the same cable drops 1.83mV.

Temperature correction is 4% increase in resistance per 10[/FONT][FONT=Tahoma, sans-serif]°C[/FONT][FONT=Tahoma, sans-serif]increase in temperature, i.e. 20% for a 50[/FONT][FONT=Tahoma, sans-serif]°C difference.


The difference in these two figures is 58%.

What's going on? [/FONT][FONT=Tahoma, sans-serif] [/FONT]

[FONT=Tahoma, sans-serif]
[/FONT]

 

[scotsparky]

back pages of OSG about page 120ish gives you resistive values of cables as well as values for CPCs the vold drop calcs mainly use the values in appendix4 so the info is there int both books they want to know if you can adjust calcs to suit the info. 75% of the exam is interpritation of the questions. once yu can do that the rest is easy i completed mine in less than 2 hours and still passed

 

[GStueyXR]

To be fair tho scot, every past paper I ever done was easy.....

Thursdays paper was a fricken nightmare

 

[scotsparky]

I doubled the length of the conductors, but now I'm confused:

Table 4D1B in Appendix 4 states that 10mm sq cable in conduit drops 4.4mV/A/m at 70 [FONT=Tahoma, sans-serif]°[/FONT]C
The title at the top states:[FONT=Tahoma, sans-serif] 'Single-core ... cables', [/FONT]so I'd assume the values are for one conductor only.

The table in the question paper is different. 'Figure 1 below shows information on the resistance of conductors in mΩ/A/m.'
[FONT=Tahoma, sans-serif]The bottom row says nothing more than: 1m of a 10mm² conductor has a resistance of 1.83m[/FONT]Ω at 20[FONT=Tahoma, sans-serif]°C.[/FONT]
[FONT=Tahoma, sans-serif]At 1amp, this gives a voltage drop of 1.83mV.[/FONT]
[FONT=Tahoma, sans-serif]The scenario also mentions single cables in trunking and conduit.[/FONT]

[FONT=Tahoma, sans-serif]Sadly, when I compare the figures with BS7671, logic and common-sense cease to apply.[/FONT]
[FONT=Tahoma, sans-serif]The values on the exam paper should be the same as the values listed in BS7671, table 4D1B, but reduced a certain amount because they're at [/FONT]20[FONT=Tahoma, sans-serif]°C[/FONT][FONT=Tahoma, sans-serif] instead of 70.[/FONT]

[FONT=Tahoma, sans-serif]BS7671 says a 1m length of 10mm [/FONT][FONT=Tahoma, sans-serif]²[/FONT][FONT=Tahoma, sans-serif] cable drops 4.4V per amp,[/FONT]
[FONT=Tahoma, sans-serif]C&G say that the same cable drops 1.83mV.[/FONT]

[FONT=Tahoma, sans-serif]Temperature correction is 4% increase in resistance per 10[/FONT][FONT=Tahoma, sans-serif]°C[/FONT][FONT=Tahoma, sans-serif]increase in temperature, i.e. 20% for a 50[/FONT][FONT=Tahoma, sans-serif]°C difference.[/FONT]


[FONT=Tahoma, sans-serif]The difference in these two figures is 58%.[/FONT]

[FONT=Tahoma, sans-serif]What's going on? [/FONT]

the single core reffert to the type of wiring if you look through all cable types have different values for different cables.

when using the tables use the corrrect refrence e.g on tray,clipped direct,burried etc.

as for the differnces in the resistances its related to the temp. i dont have books nearby most info is from memory but i thin the No in OSG are for 20degc and the BRB are at 70c

 

[Charles West]

Thanks Scotsparky, OSG seems to be clear in saying that values are for a 'length of run in metres'. It does make more sense to give figures for voltage dropped on the cable length, rather than individual conductors. I assume it's the same for the values in BS7671, which would explain the 58% difference in the values given in the exam.
The values in the exam are for one conductor. The remaining 8% is the temperature difference (I thought it would be 20% for temperature, but percentages do weird things depending on which way you divide/multiply them).

 

[Charles West]

I will not argue that... My argument is the neutral puts up a resistance... So it must therefore be built into the calculations in the tables. There is no need to seperate them, after all L and N conductors must be equal size.

BUT, we were not given tabulated values of Vdrop.

I agree. Values of voltage drop make sense if you include both conductors, but the question gave resistance of conductors, and needed you to recognise that there are two cables presenting this resistance. You needed to double the length.

 

[T&Earth]

Hi Guys

Also did this paper and would like to get a copy, to help me when I resit it in October!!

Many Thank

PS I also did not understand first question and most of the others

Steve

 

[CRAGS]

Hi Guys

Also did this paper and would like to get a copy, to help me when I resit it in October!!

Many Thank

PS I also did not understand first question and most of the others

Steve

Join the club!!!! If you want a copy pm me your email and I will send it out to you

 

[SafetyFirst]

There seems to be a unanimous conclusion that these 2391 exams aren't worded very well. How many folks took this exam on here? I'm thinkin we should start a revoloution or something, at the least get a petition sent out to ****** and no thrills telling them that whoever writes out this exam wants sacking!!!

 

[brucelee]

agree mate but they a law unto themselves

 

[mag8485]

I doubled the length of the conductors, but now I'm confused:

Table 4D1B in Appendix 4 states that 10mm sq cable in conduit drops 4.4mV/A/m at 70 °C
The title at the top states: 'Single-core ... cables', so I'd assume the values are for one conductor only.

The table in the question paper is different. 'Figure 1 below shows information on the resistance of conductors in mΩ/A/m.'
The bottom row says nothing more than: 1m of a 10mm² conductor has a resistance of 1.83mΩ at 20°C.
At 1amp, this gives a voltage drop of 1.83mV.
The scenario also mentions single cables in trunking and conduit.

Sadly, when I compare the figures with BS7671, logic and common-sense cease to apply.
The values on the exam paper should be the same as the values listed in BS7671, table 4D1B, but reduced a certain amount because they're at 20°C instead of 70.

BS7671 says a 1m length of 10mm ² cable drops 4.4V per amp,
C&G say that the same cable drops 1.83mV.

Temperature correction is 4% increase in resistance per 10°Cincrease in temperature, i.e. 20% for a 50°C difference.


The difference in these two figures is 58%.

What's going on?

The 4.4 mV/A/m is for 2 cables (L+N) single phase 10mm copper conductor at 70 degrees.
if you divide that by 2 you get 2.2 mV/A/m for one 10mm conductor at 70 degrees

The mV/A/m value is doubled to add the neutral conductor so you dont need to double the length. Just use the length of the run.

The 1.83mΩ/m is at 20 degrees.
Temperature correction is 4% increase in resistance per 10°Cincrease in temperature, i.e. 20% for a 50°C difference.

so 1.83 x 1.2 (20%) = 2.2mΩ/m (at 70 degrees)

mV/A/m is the same as mΩ/m