Discuss Volt drop cont. in the UK Electrical Forum area at ElectriciansForums.net

I'm sorry to be a pain but surely the second measurement isn't from the cu with the remaining loads. It's from the first light. Otherwise you will be measuring the same length of cable from the CU multiple times. Correct me where I'm being stupid please.
 
You wouldn't calculate vd that way unless you add extra load to an existing cct, vd is calculated for the full load at it's furthest point.

If you've got multiple loads in a circuit, that gives you the worst case.
So if you were close/above to max VD% and had to up cable csa, then you can calculate the VD at each load/sections of the circuit, that will keep you within limits then.
 
You wouldn't calculate vd that way unless you add extra load to an existing cct, vd is calculated for the full load at it's furthest point. The vd is calculated from the origin of supply in all cases, a good example is where you have sub mains.

But on lighting circuits your dropping loads at various points and lengths. So you can't measure full load from
CU to furthest point, as it would be incorrect???
 
But on lighting circuits your dropping loads at various points and lengths. So you can't measure full load from
CU to furthest point, as it would be incorrect???

The ONLY volt drop you MUST be concerned with is that at the origin of supply, all the rest is stuff and nonsense. It is at the origin of the supply where Volt drop will make it's presence felt and where it will have the biggest impact on the voltage on the circuit.

If you worry about it down the line then your wasting your time and will likely install a complete bodge.
 
Again outspoken I truly am sorry for sounding like an idiot but I don't know what you mean. I understood VD as something that occurred in circuits current x length of cable (resistance) = VD. What do you mean when you say at origin of supply.
 
Again outspoken I truly am sorry for sounding like an idiot but I don't know what you mean. I understood VD as something that occurred in circuits current x length of cable (resistance) = VD. What do you mean when you say at origin of supply.

OK, a circuit starts in a consumer unit or distribution board, the origin of the supply for an individual circuit will be the circuit protective device (RCD/MCB/RCBO/Fuse). Technically it should be at the true origin, but the volt drop between your head and consumer unit will be negligible due to the conductor size and loading on the system, it is only an issue in commercial/industrial installs and then only when Tommy Clarkes have done the designing :D
 
The ONLY volt drop you MUST be concerned with is that at the origin of supply, all the rest is stuff and nonsense. It is at the origin of the supply where Volt drop will make it's presence felt and where it will have the biggest impact on the voltage on the circuit.

If you worry about it down the line then your wasting your time and will likely install a complete bodge.



OK, a circuit starts in a consumer unit or distribution board, the origin of the supply for an individual circuit will be the circuit protective device (RCD/MCB/RCBO/Fuse). Technically it should be at the true origin, but the volt drop between your head and consumer unit will be negligible due to the conductor size and loading on the system, it is only an issue in commercial/industrial installs and then only when Tommy Clarkes have done the designing :D

I'm not sure i'm missing something here or not, but ....
I'm not quite following what your saying here?? What has the voltage at the origin (apart from complying with said norms, eg, 240 true/230 make believe) got to do with calculating the volt drop of a branch circuit over given distances and known loads?? We have formula's for calculating VD regardless of what the voltage present at the origin is, ....that voltage will typically remain constant, it's the design of the circuit and the cable/conductors sizes selected, that will determine if a VD anywhere on that branch circuit complies or doesn't comply....
 
Sorry outspoken were not communicating properly. My fault. Yeah I understand from origin to furthest point is the VD which needs to comply. What I'm talking about is getting to certain points along branch circuits and deducting a long the way due to different loads being dropped. I know it's alway from origin. Just trying to point out that at a joint in a lighting circuit or feed in and feed out and a cable to the light they will all be at the same voltage, sort of the particular branches origin of supply. Just it will have been reduced to voltage being dropped before said joint.
 
Monkeyblaine I think your method of explaining can leave others wondering what you mean (and possibly me as well!).
However I believe that what you are saying is that if you have a branched radial circuit then the volt drop of one branch is not added to other branches.
In this you would be correct.
If you assume you have a circuit with a supply cable going to a junction box and then splitting to two cables (one going left, one going right) each of which has two luminaires, each at a different point along the cable.
The volt crop calculation would include the cable from the CU to the point of the first branch for the full load of the whole circuit; added to that would be the volt drop to the first luminaire on the left hand branch using the current load for two luminaires; added to that would be the volt drop to the last luminiare on the left hand branch using the current for the last luminaire. This would give the max volt drop for the left hand branch.

Then you would calculate in the same way for the supply cable, the cable to the first luminaire on the right hand branch and the cable to the last luminaire of the right hand branch. This would give you the maximum volt drop on the right hand branch.

The highest of the left hand and right hand calculations would be the maximum volt drop for the whole circuit.
 
Ahhhh ok. So that makes sense. You don't need to be Adding all VD of branches. Just worse case scenario at furthest point. Where it's going to be a problem. That's all I was trying to establish. Because in that case it gets mega confusing. I'm sorry for being rubbish at explaining things I'm sure I'm very frustrating. Thank you everyone for being patient and helping me.
 

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