cliffed

-
Arms
Would you guys be happy with these readings on ring main,Rcbo c type 30ma/32 amp.
r1 1.87...rn 1.91 cpc 3.20....R1 +R2.1.26.
zs 1.46 ohms.
 
It is quite a long circuit, but from the fact that it is a C32 RCBO, I'm suspecting this is commercial / industrial, rather than domestic? For example, a ring in a large workshop, warehouse, school, etc.

I'd be wondering about the voltage drop, e.g. are all the loads at middle of the ring because the outlets happen to be a long way from the distribution board?

Or has someone used a somewhat too small cable size, e.g. 1.5mm2 T&E or SWA?
 
It’s in a quite a large office area,it’s defo 2.5mm,difficult to judge where the actual loads are,there are mainly,computers plugged in.Been in service @ least 5 years,all signed of.
 
It’s in a quite a large office area,it’s defo 2.5mm,difficult to judge where the actual loads are,there are mainly,computers plugged in.Been in service @ least 5 years,all signed of.
if that's the case, why not replace MCB with a B type, even drop to a 20A?
 
Sorry to hijack the post but for someone still learning how do you work out the length of circuit from the readings ie what would the formula be please ? Tia
Look in the on-site guide, appendix, I think it's table 11

It gives the R1+R2 resistance per metre

So for 2.5/1.5 it's around 19.5 miliohm per metre if you know the length, it's length x this value, if you know the overall resistance it's the resistance devided by the resistance per metre

You could also work it out from R1 for 2.5mm2 per metre, plus R2 for 1.5mm2 per metre

These values are also in the table
 
For a ring final, use an end-to-end reading, eg. the line conductor r1.

Length of conductor = resistance of conductor ÷ resistance of conductor per meter

For a 2.5mm² conductor, resistance per meter is 7.41mΩ, or 0.00741Ω. So:

Length of conductor = r1 ÷ 0.00741
 

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cliffed

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Eicr ring main readings
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