Stuck on an assignment for college

[LotusBiscuit]

The question is:
If the supply voltage is 100v ac with a period of 20ms, and the supply current (Is) taken by the coil is 6A, calculate the frequency of the supply, overall impedance, Inductive reactance and the inductance of the coil.

I've worked out the frequency to be 50Hz and in order to get the Inductive reactance I need to work out the inductance of the coil.

f = 1/t
1/20ms

1/20x10^-3 = 50hz
Z = v/I
Z= 100/6
Z =17.6

Xl = sqroot z^2 - r^2
17.66^2 - 100 = 13.24

2pifl
L =xl ÷ 2pif
13.24 ÷ 2 x pi x 50=
0.04H

Just want to double check any help??

 

[pc1966]

Note you do not have a resistance in the question, or did it give a DC resistance as well?

Also 100/6 = 16.666... = 16.67

Without knowing any R, assume it is all inductive reactance Xl = 2 * PI * f * L

L = Xl / (2 * PI * f) = 16.67 / (2 * 3.141592 * 50) = 0.053 H

 

[LotusBiscuit]

Note you do not have a resistance in the question, or did it give a DC resistance as well?

Also 100/6 = 16.666... = 16.67

Without knowing any R, assume it is all inductive reactance Xl = 2 * PI * f * L

L = Xl / (2 * PI * f) = 16.67 / (2 * 3.141592 * 50) = 0.053 H

No it didn't mention the resistance in the question, however I used ohms law to work it out.

I did V/I = R
So 100/6 = 16.67 ohms

Thanks a lot for the help, looks like I've made a couple mistakes ?

 

[Julie.]

No it didn't mention the resistance in the question, however I used ohms law to work it out.

I did V/I = R
So 100/6 = 16.67 ohms

Thanks a lot for the help, looks like I've made a couple mistakes ?

If you say

Z = V/I = 16.7 ohm
AND
R =V/I = 16.7 ohm

Then XL must be zero! (Try XL^2 = Z^2 - R^2)

You have no idea what the resistance is unless it is given in the question, with ac circuits if you only have the voltage and current, all you can calculate is the Impedance Z.

You then decide how this is split between the resistance, and reactance(s) based on the question, in this case it doesn't give resistance and only highlights inductance, so you have to assume all the Z is from the inductance.

So given XL = 16.7 ohm at 50Hz the inductance will be 16.7/(100 pi)

 

[LotusBiscuit]

If you say

Z = V/I = 16.7 ohm
AND
R =V/I = 16.7 ohm

Then XL must be zero! (Try XL^2 = Z^2 - R^2)

You have no idea what the resistance is unless it is given in the question, with ac circuits if you only have the voltage and current, all you can calculate is the Impedance Z.

You then decide how this is split between the resistance, and reactance(s) based on the question, in this case it doesn't give resistance and only highlights inductance, so you have to assume all the Z is from the inductance.

So given XL = 16.7 ohm at 50Hz the inductance will be 16.7/(100 pi)

Oh ok, so ohms law is only applicable for dc circuits?

 

[LotusBiscuit]

If you say

Z = V/I = 16.7 ohm
AND
R =V/I = 16.7 ohm

Then XL must be zero! (Try XL^2 = Z^2 - R^2)

You have no idea what the resistance is unless it is given in the question, with ac circuits if you only have the voltage and current, all you can calculate is the Impedance Z.

You then decide how this is split between the resistance, and reactance(s) based on the question, in this case it doesn't give resistance and only highlights inductance, so you have to assume all the Z is from the inductance.

So given XL = 16.7 ohm at 50Hz the inductance will be 16.7/(100 pi)

Ok so then how would i work out the power factor, I dont have the resistance given to me nor can I work it out? So rules out cos phi = R/Z

Would i do sin phi = Xl/Z??

 

[LotusBiscuit]

Ok so then how would i work out the power factor, I dont have the resistance given to me nor can I work it out? So rules out cos phi = R/Z

Would i do sin phi = Xl/Z??

I'm lost ??
For the power factor I'd do R/ V x I?

 

[Julie.]

Oh ok, so ohms law is only applicable for dc circuits?

Ohms law can be used for both ac and dc, however with ac it will give you the impedance of the circuit not resistance, and dc will give you the resistance.

 

[Julie.]

Ok so then how would i work out the power factor, I dont have the resistance given to me nor can I work it out? So rules out cos phi = R/Z

Would i do sin phi = Xl/Z??

It doesn't ask for the power factor, and for good reason - it doesn't provide enough information.
If it gave you resistance then you could.

The question could be:

With ac 50Hz you have 6A at 100V
With dc you have 20A at 100V

In which case you could work out the Z from the ac values and the R from the dc values. Given these you could then get the resistance, reactance, inductance, and power factor.

But as it only gives the ac without resistance you can't do it

 

[LotusBiscuit]

It doesn't ask for the power factor, and for good reason - it doesn't provide enough information.
If it gave you resistance then you could.

The question could be:

With ac 50Hz you have 6A at 100V
With dc you have 20A at 100V

In which case you could work out the Z from the ac values and the R from the dc values. Given these you could then get the resistance, reactance, inductance, and power factor.

But as it only gives the ac without resistance you can't do it

No it doesn't ask for the power factor in that question however on the next question it asks me to "calculate the power factor and the phase angle of the coil". So I assume its to do with the previous question being the one i mentioned.

 

[Julie.]

No it doesn't ask for the power factor in that question however on the next question it asks me to "calculate the power factor and the phase angle of the coil". So I assume its to do with the previous question being the one i mentioned.

Ah, OK

In that case, either they give the resistance somewhere, or you know the phase angle and power factor without calculation.

 

[LotusBiscuit]

Ah, OK

In that case, either they give the resistance somewhere, or you know the phase angle and power factor without calculation.

Referring to question 2c and 2d, neither the resistance nor power factor and phase angle are given.

 

[pc1966]

Question (2a) has your DC aspect, from that you can compute R, and from Z from (2c) you can then compute Xl separately to get L.

From Xl and R you can compute your power factor / phase angle for (2d)

#1 tip for examinations - read the questions carefully as often the examiner is leading you towards a solution by the order of things you are asked for.

#2 tip - sometimes you get too much information, so be prepared to locate the stuff you need.

 

[LotusBiscuit]

Question (2a) has your DC aspect, from that you can compute R, and from Z from (2c) you can then compute Xl separately to get L.

From Xl and R you can compute your power factor / phase angle for (2d)

#1 tip for examinations - read the questions carefully as often the examiner is leading you towards a solution by the order of things you are asked for.

#2 tip - sometimes you get too much information, so be prepared to locate the stuff you need.

Oh wow, I just realised that all those questions are about the same coil, it all is starting to make sense, thank you.

 

[Julie.]

Referring to question 2c and 2d, neither the resistance nor power factor and phase angle are given.

Yes they are; the resistance can be calculated from the previous part of the question - exactly how I suggested previously.

You calculate the dc resistance from that portion of the question, the impedance Z from the ac part giving Z and R, therefore you can calculate pf and phase angle


You really need to look at the whole question - just selecting one aspect will not give the whole answer

 

[LotusBiscuit]

Yes they are; the resistance can be calculated from the previous part of the question - exactly how I suggested previously.

You calculate the dc resistance from that portion of the question, the impedance Z from the ac part giving Z and R, therefore you can calculate pf and phase angle


You really need to look at the whole question - just selecting one aspect will not give the whole answer

Ok so,

So the resistance that i got from the DC part of the question is 100v / 10A = 10ohms

Therefore the powerfactor would be R/Z = 10/ (100/6) = 10/16.7 = 0.59....

And for the phase angle I am unsure about the equation, I've googled it and got; Angle = tan^-1(Xl-Xc/R) just want to double check that before I write it down

Thank you

 

[Julie.]

Ok so,

So the resistance that i got from the DC part of the question is 100v / 10A = 10ohms

Therefore the powerfactor would be R/Z = 10/ (100/6) = 10/16.7 = 0.59....

And for the phase angle I am unsure about the equation, I've googled it and got; Angle = tan^-1(Xl-Xc/R) just want to double check that before I write it down

Thank you

If you do R/Z, you could just use cos^-1 (arc-cos) of the pf - R/Z is the pf

Or if you do X/Z you could use sin^-1 (arc-sin) of X/Z

Or if you do X/R you use tan^-1 (arc-tan) of X/R

Do a search for an online tutorial about power triangle on ac circuits, or impedance triangle on ac circuits, try a few until it clicks with you

 

[Copperfield]

'Hey, I'm actually doing the same assignment atm and im stuck on a few of these questions i.e question 2f, 2g, 2h, 2i and 5, 8 and 9 lol. My teacher isn't helping me out at all with them. Would you be able to shed some light on them for me please?

Thanks!

 

[Lister1987]

'Hey, I'm actually doing the same assignment atm and im stuck on a few of these questions i.e question 2f, 2g, 2h, 2i and 5, 8 and 9 lol. My teacher isn't helping me out at all with them. Would you be able to shed some light on them for me please?

Thanks!

Work thr calculations in order and you should be fine.

Remember you'll like get marks for each part;

Circuit Diagram - Draw thr Circuit out and label it.

Formula to be used

Formula with values substituted in

Power Triangle

Impedance Triangle

Phasor Diagram

That way even of your end result is wrong, the assessor can see how you got there and award marks for the correct steps

 

[Lister1987]

https://youtube.com/playlist?list=PL7eNzIRgKe07BOqPH7MrrKy89M3o4wU-2

This playlist should help.

 

[MohamedMohamed]

The question is:
If the supply voltage is 100v ac with a period of 20ms, and the supply current (Is) taken by the coil is 6A, calculate the frequency of the supply, overall impedance, Inductive reactance and the inductance of the coil.

I've worked out the frequency to be 50Hz and in order to get the Inductive reactance I need to work out the inductance of the coil.

f = 1/t
1/20ms

1/20x10^-3 = 50hz
Z = v/I
Z= 100/6
Z =17.6

Xl = sqroot z^2 - r^2
17.66^2 - 100 = 13.24

2pifl
L =xl ÷ 2pif
13.24 ÷ 2 x pi x 50=
0.04H

Just want to double check any help??

Xl = sqroot z^2 - r^2
17.66^2 - 100 = 13.24 can you explain this part please
thanks