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Penance

Pre empting my 2382 and trying to calculate lb so as I can calculate voltage drop.

Circuit I have used for this is an upstairs lighting circuit, 1mm2 t&e 4 light points and length of approx 19m.

Cable installed to ref method C.

Getting myself a bit confused but this is what I think I should be doing:

Using the OSG app 5 table 1a I assume a load of 400 watts, 1.818A.
Is this actually lb or should I apply diversity?
 
Apply diversity, apply de-rating factors, such as insulation, ambient temp, 3036 rule etc, that will give you your IB then MV/M/A x IB x L / 1000

Sorry don't have osg or brb with me to work out any examples for u
 
use worst case scenario. design for max. loading. i would round off Ib to 2A, then calculate volt drop from that. just makes it easier all round. if you want to allow for future expansion , though, allow for an extra point or 2. i.e. 600watts, 2.6A, round up to 3A.
 
So do I round up to 2A then apply 66% diversity?
Cable is either direct in plaster (from CU to loft) or clipped direct to joists in loft, at each lighting point the cable passes thru approx 400mm of plastic conduit to keep insulation from direct contact, is ref method C correct for this?
Do I assume ambient temp to be around 20•c for a domestic property, that's what we normally have the stat at on the heating?
Protective device is 6A type B mcb so does 3036 apply?
 
Thought so.

What you say about worse case makes sense to me but does that mean I should not apply diversity as that would lower lb?

Yup IB after application of diversity and application of appropriate de-ration factors, sorry for the bum steer regarding 3036's I should have explained further, my apologies it only applies to semi enclosed bs3036 fuses and is a value of .75
 
Here goes-

4 lighting points on circuit assumed at 100W each gives 400W or 1.818A.

Applied diversity of 66% gives 1.199.

Ambient temp of 20•c correction factor of 1.04
1.04 * 1.199 = 1.246.

Mv/A/m for 1mm2 conductor with ref method C = 44
Lb = 1.246
circuit length = 19m

Voltage drop -
(44 * 1.246 * 19) / 1000 = 1.041
 
Thanks mate, is there anything else I'll need to calculate?
I know I have to do final ring cooler etc but is it just v drop and ensuring csa is suitable after corrections?
 
We're old fashioned and use tap mixers so no issue there, obviously something I'll need to know about.
Could you outline an install for me and I'll see if I can do the calcs?
 
how do you know , what percentage to apply for diversity in circuits. where do you's get this info from, sorry for hijackin. i know cooker is first 10A plus 30% thansk
 
10.5Kw = 45.652A

No diversity applied, have taken it to be an instantaneous heater so 100% of load.

Ambient temp of 30c correction factor of 1.08
1.08 * 45.652 = 49.304

No conductor CSA specified but would need to be minimum of 10mm2 but with installation ref method 101 10mm2 is rated at 36A.

Using 16mm2 with ref method 101 allows 46A.

Me thinks you need to reroute cables and not under Insulation.

So go on, where did I go wrong?

 
what table does 1.08 come from for ambient air temp of 30 celcius?

And the formula for It is

It = Ib/(Ca*Cg* Ci* Cc) so that would be dividing not multiplying

Also table 6B of OSG or 52.2 of BRB is needed for the insulation to give you the factor for Cc

checkout p123 of OSG and tables 6A and 6B on the next 2 pages :)

edit - suppose could use method 101 for cable
 
Last edited by a moderator:
1.08 came from table 2e page 104 OSG.
Think I may be using the wrong table.

The formula you showed is for current carrying capacity, I got the max rated current from table 6f page 134 OSG. Is that wrong?
 
1.08 came from table 2e page 104 OSG.
Think I may be using the wrong table.

Yep you are using the correction factors for Zs

The formula you showed is for current carrying capacity, I got the max rated current from table 6f page 134 OSG. Is that wrong?

That is ok if you do it that way but if there are a variety of simultaneous factors you would have to work out It and then go to a table like 4D2A in the brb to select your cable size.

Table 4D5 of brb or 6F of OSG are fine if you can get a direct match to installation method.
 
two or more cables grouped together, higher ambient temps, running straight thru thermal insulation (had not read thru the method of installation, for your last example, properly when i commented initially) also could be on a rewireable to BS3036. You only use the worse case factors that are occuring at the same time. eg if it ran thru a metre of insulation and later the cable went thru a boiler house at higher ambient temp you would only use the insulation factor as that is the worst one and they are not occuring at the same time.
 
Cool, thanks.
Answers my question about multiple methods on same cable run. I assumed you should take worse case.

Will do bd calc in a while.
 
Here goes, assuming cable has now been sorted and is clipped direct for whole run.
Lb = 45.652
30c ambient correction = 1
mv/a/m for 10mm2 using ref method c is 4.4 -
(4.4 * 45.652 * 26.5) / 1000 = 5.323

So if now clipped direct 10mm2 t&e with 50a type b mcb will be ok

I think!
 
Yeah it is a close run thing - 10mm on a 50A breaker gives lots of leeway and would be the sensible choice if you were installing. If, however, the 6mm cable was already in place and you were being asked to fit the 10.5kW shower you could just comply with a 45A mcb.

At 8.8V on the 6mm² the volt drop is still within 5% .
Hope this has helped a bit :)


edit : 4D5 of brb (the table for T&E) gives 6mm² at 47A
 
Last edited by a moderator:
Yes mate, it all helps.

I think I may have been using wrong table in OSG. Saying that I would still be happier installing 10mm on a 50a mcb.
 

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