Currently reading:
electrical installation certificate

Discuss electrical installation certificate in the Periodic Inspection Reporting & Certification area at ElectriciansForums.net

Maximum demand (often referred to as MD) is the largest current normally carried by circuits, switches and protective devices; it does not include the levels of current flowing under overload or short circuit conditions, Assessment of maximum demand is sometimes straightforward. For example, the maximum demand of a 240 V single-phase 8 kW shower heater can be calculated by dividing the power (8 kW) by the voltage (240 V) to give a current of 33.3 A. This calculation assumes a power factor of unity, which is a reasonable assumption for such a purely resistive load.
There are times, however, when assessment of maximum demand is less obvious. For example, if a ring circuit feeds fifteen 13 A sockets, the maximum demand clearly should not be 15 x 13 = 195 A, if only because the circuit protection will not be rated at more than 32 A. Some 13 A sockets may feed table lamps with 60 W lamps fitted, whilst others may feed 3 kW washing machines; others again may not be loaded at all. Guidance is given in {Table 6.1}.
Lighting circuits pose a special problem when determining MD. Each lamp-holder must be assumed to carry the current required by the connected load, subject to a minimum loading of 100 W per lampholder (a demand of 0.42 A per lampholder at 240 V). Discharge lamps are particularly difficult to assess, and current cannot be calculated simply by dividing lamp power by supply voltage. The reasons for this are:
1. - control gear losses result in additional current,
2. - the power factor is usually less than unity so current is greater, and
3. - chokes and other control gear usually distort the waveform of the current so that it contains harmonics which are additional to the fundamental supply current.
So long as the power factor of a discharge lighting circuit is not less than 0.85, the current demand for the circuit can be calculated from:
current (A) =
lamp power (W) x 1.8
supply voltage (V)​
For example, the steady state current demand of a 240 V circuit supplying ten 65 W fluorescent lamps would be:
I =
10 x 65 x 1.8 A​
= 4.88A
240​
Switches for circuits feeding discharge lamps must be rated at twice the current they are required to carry, unless they have been specially constructed to withstand the severe arcing resulting from the switching of such inductive and capacitive loads.
Table 6.1 - Current demand of outlets
Type of outletAssumed current demand
2 A socket outletAt least 0.5A
Other socket outletsRated current
Lighting pointConnected load, with minimum of 100 W
Shaver outlet, bell transformer or any equipment of 5 W or lessMay be neglected
Household cooker10A + 30% of remainder + 5A for socket in cooker unit
When assessing maximum demand, account must he taken of the possible growth in demand during the life of the installation. Apart from indicating that maximum demand must be assessed, the Regulations themselves give little help. Suggestions for the assumed current demand of various types of outlet are shown in {Table 6.1}.
 
thank you so much, basically im attending the 2399-11 solar pv installation course next month and it states you have to be competant at inspection and testing which i am not. i am basically trying to teach myself and finding it tough
 
The only way your going to get "competent" is testing with another test engineer, or just keep reading your regs and GN books as much as you can. cant help much more sorry mate.
 
im just hopeing if i learn enough with my "practical guide to testing" book then in the course they will go through the testing with us? kinda need someone who has attended.
and thanks again "widdler" very much apprieciated
 
Test at home at weekends until you feel confident, carry out safe isolation of course, i take it you have a meter as doing practicals is better than theory every time. Carry out tests and figure out what the results mean as well, dont just write the figures down.
 
Jumpin jax- I'm an electrician, I have mainly worked on fire alarm systems and now as a controls electrician so havent done too much domestic installs or testing but feel like im starting to get there with this testing book
 

Reply to electrical installation certificate in the Periodic Inspection Reporting & Certification area at ElectriciansForums.net

OFFICIAL SPONSORS

Electrical Goods - Electrical Tools - Brand Names Electrician Courses Green Electrical Goods PCB Way Electrical Goods - Electrical Tools - Brand Names Pushfit Wire Connectors Electric Underfloor Heating Electrician Courses
These Official Forum Sponsors May Provide Discounts to Regular Forum Members - If you would like to sponsor us then CLICK HERE and post a thread with who you are, and we'll send you some stats etc

YOUR Unread Posts

This website was designed, optimised and is hosted by untold.media Operating under the name Untold Media since 2001.
Back
Top
AdBlock Detected

We get it, advertisements are annoying!

Sure, ad-blocking software does a great job at blocking ads, but it also blocks useful features of our website. For the best site experience please disable your AdBlocker.

I've Disabled AdBlock