Calculating volt drop, cable selection and mcb selection on an 3kw motor

[Sparky Ninja]

another..

3.

An upstairs lighting circuit is wired in thermoplastic insulated and sheathed twin and CPC cable. The cable is buried within the fabric of the building. It is run with insulation surrounding it for a distance of 0.5m, although its total length is 30m. There are 8 x 230V GLS lights on the circuit, and the circuit is protected by a 5A BS 3036 fuse. If the ambient temperature is 30 degrees C and there is no grouping, determine an appropriate cable size.

i) Design current
ii) Rating of protective device
iii) Current-carrying capacity of the cable
iv) Volt drop within the cable

I have some maximum demand questions ready and waiting too..

 

[daiplayer]

many many many thanks for taking the time to teach a bit mate. My tutors are known for being ...er...****e...

Hence the reason for seekin help.

Any more q's would be much apprieciated ( around all the subjects) ....Thanks again

 

[daiplayer]

now thats thrown me....Do i consider the cable to be in insulation ?
Do i need to confirm the protective device rating if it is given ? (check it maybe ? )

 

[daiplayer]

Ib = 3.47A
=1mm cable
=fuse 5A

volt drop : 44x3.47x30/100 = 4.58v ?

 

[Sparky Ninja]

Spot on

Hopefully you would have had a correction rating of 0.5 for Ci, giving you a current-carrying capacity of 7A = 1.0mm / 15Amp

I had 4.62V, but that's because I rounded some of my figures up.

 

[daiplayer]

...success....!!! good tutor you see ;-)

 

[Sparky Ninja]

now thats thrown me....Do i consider the cable to be in insulation ?
Do i need to confirm the protective device rating if it is given ? (check it maybe ? )

Yes for the length described, and always as it could be provided incorrect to mislead you.

 

[daiplayer]

sneaky sneaky...lol

 

[Sparky Ninja]

I want to give you one last question on cable selection (to allow for 400V) then we can do some maximum demand/diversity and adiabatics (sizing of protective conductor)

4.

A 25kW, 400 V three-phase heater is wired in thermoplastic sheathed MICC cable fixed to horizontal perforated cable tray. The circuit is run with two other circuits and the maximum permitted volt drop is 6 V. The length of run is 28m and the heater is protected by a BS EN 60898 Type B triple pole circuit-breaker. The ambient temperature is 35 degrees C.

i) Design current
ii) Rating of protective device
iii) Current-carrying capacity of the cable
iv) Volt drop within the cable

 

[pushrod]

Spot on




Selecting cable too soon.. will waste time in your exam



You've selected the correct factors etc, so if you put these workings down you would get a good quantity of the mark. However one thing you need to consider is the potential of overload.
The question reads 'heating load', not 'load' or 'sockets'. Because of this we can assume that the heater is of a fixed rating and so overload won't occur.
This therefore means that instead of using (In) divided by the correction factors, we could instead use (Ib).
It also means that the Cc factor of 0.725 (due to the BS3036 fuse) can also be omitted from the formula.

So the formula can be put down as:

It= Ib/(CaxCg)

= 13A/(0.80x1.03) = 15.7A

So from table 4D2A Column 6 we can pick a tabulated current-carrying capacity = 1.5mm carries 19.5A

Much respect to you Widdler for putting so much time and effort in. One very small point which doesn't affect the outcome at all. The question said

buried within the building material of the installation

So wouldn't that mean ref method B [42 from table 4A2?] not ref method C, so table 4D2A column 4 = 1.5mm² carries 16.5A

or am i wrong ?