Cant remember studying this but if anyone can help me out that that would be sweet

[lofty84]

Hi im reviseing for my 203 and this question has got me stumped its a bit hard to draw it out exactly as tthe lines do not match up but its basically two lines that form a right angle with an arrow head on the end of them.

Its quite hard trying to remember things as if you failed an exam you just moved on as the resists weremonths away. Haveing got through everything else it would be nice to get this one under my belt so its just the 301, 302, and 303 to do but I dont remember looking at things like this.




_ _ _ _ _ _ _ _ _ _ > I ref
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V

V (this is the letter V)

the possible answers are

a. purely resistive
b.purely capacitive
c.resistor and inductor in series
d.purely inductive

the answer is b (purely capacitive) but why is this is the picture supposed to be showing me something

thankyou

 

[amer]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Thanks to everyone whos tried to help me. Really is much appreciated.

in regards to the sq root of three the 1.732 does that only comeinto play on three thase systems ?

yes you are right only in 3 phase

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

The voltage supplied to the primary winding of a step down transformer is 660v and the output voltage is 230v. If the primary current is 12A the value of the secondary current will be.

Would the answer be 660/230 x 12 = 34.4

 

[amer]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Is= VP*Ip/ Vs 660 * 12 =7920 / 230 =34.4

 

[pushrod]

Re: Cant remember studying this but if snyone can help me out that that would be swee

This isnt looking good but at least ive given myself a chance by starting the revision early

How many numbers of turns are needed on a transformer if the primary windings are 1000 and the primary and secondary currents are 5 A and 20 A respectivly.

the options are

a. 200 turns
b.250 turns
c.100 turns
d. 50 turns

the answers b and i did come to that conclusion but was the way i did it right.

I said 1000/5 = 200

and 1000/20= 50

I then addedthem together

The way to do it is with ratios if the number of turns increases 5 times then the voltage increases 5 times. Hower with transformers it's the opposite way around with I and V, if the current increases by , say, 10 times then the voltage decreases by 10 times - and vice versa.

In your example the the current has increased from 5A to 20A (20/5 =4) so it has increased 4 times.
That means the voltage must decrease by 4x . Also that the number of turns has decreased by 4x.
so 1000 turns /4 = your answer (250 turns) hope that helps a bit

 

[pushrod]

Re: Cant remember studying this but if snyone can help me out that that would be swee

How do you get the input lower than the output think you will find the answer is A

the input power is in kw and is just the power dissipated in the resistance, whereas the apparent power kVA takes account of the current used to generate magnetic fields as well. (It is the hypotenuse on the triangle so will be bigger than the adjacent)

It is not like saying you are getting out more power out than you are putting in.

The extra current for the apparent power is still there and this is why you have to calculate your cable size on the apparent power not the true power with inductive loads.

This is why there are always so many questions/problems on here when people are working with inductive lighting - they do there calcs with the power (kW) not the apparent power (kVA).

edit: the correct answer is c.

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Thanks to everyone who has got involved and helped me out.

If anyone knows how to tackle some of the harder unanswered ones it would be really helpfull

 

[pushrod]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Thanks to everyone who has got involved and helped me out.

If anyone knows how to tackle some of the harder unanswered ones it would be really helpfull

couldn't find any that were unanswered...

It is probably worth you remembering this-

" the kVA figure (apparent power) will always be bigger than the kW figure (true power)"

the only exception is if the the power factor was 1 (unity) and then they would be equal.

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Im back with some more which are confuseing me

1. A resistor and n inductor in a series circuit have a resistance of 6 (ohms) and an inductive Reactance of 8 (ohms) respectively. What is the total impedance.

The answer is 10 (ohms) but 8 + 6 is not 10

2. A transformer has a turns ratio of 400:4. If the supply voltage is 400v, what will be the secondary voltage

The answers 4 ,so does this mean that if it said it had a turns ratio of 400:10 and the supply voltage was 400v the secondary voltage would be 10 ??

Thanks

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

heres a weird one

what is the power factor of a circuit with a capacitor connectd in series, given the resistance is 6 ohms and the capacitive reactance is 8 ohms

answers are

0.6 lagging
0.75 leading
0.6 leading
0.75 lagging

completely stumped on this one

 

[Adam W]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Im back with some more which are confuseing me

1. A resistor and n inductor in a series circuit have a resistance of 6 (ohms) and an inductive Reactance of 8 (ohms) respectively. What is the total impedance.

The answer is 10 (ohms) but 8 + 6 is not 10

2. A transformer has a turns ratio of 400:4. If the supply voltage is 400v, what will be the secondary voltage

The answers 4 ,so does this mean that if it said it had a turns ratio of 400:10 and the supply voltage was 400v the secondary voltage would be 10 ??

Thanks

1.
Z = √(R² + XL²)
Z = √(6² + 8²)
Z = 10

2. The figures given are nice and easy to understand, ie 1 volt per turn, so yes if the turns ration wer 400:10 the secondary voltage would be 10.

 

[Adam W]

Re: Cant remember studying this but if snyone can help me out that that would be swee

heres a weird one

what is the power factor of a circuit with a capacitor connectd in series, given the resistance is 6 ohms and the capacitive reactance is 8 ohms

answers are

0.6 lagging
0.75 leading
0.6 leading
0.75 lagging

completely stumped on this one

pf = R ÷ Z

You have the value for R so you need to find Z first

Z = √(R²+XC²)
Z = √(6²+8²)
Z = 10


pf = R ÷ Z
pf = 6 ÷ 10
pf = 0.6

Remember the word "CIVIL" -
C I V = Capacitive, current (I) leads the voltage (V)
V I L = Inductive (L), current (I) comes after V, therefore lags.

It's a capacitive circuit, so the pf will be 0.6 leading.

 

[pushrod]

Re: Cant remember studying this but if snyone can help me out that that would be swee

heres a weird one

what is the power factor of a circuit with a capacitor connectd in series, given the resistance is 6 ohms and the capacitive reactance is 8 ohms

answers are

0.6 lagging
0.75 leading
0.6 leading
0.75 lagging

completely stumped on this one

notice the values 6 ohms and 8 ohms (multiples of 3 and 4) impedance is 10 ohms (multiple of 5)
using pythagorus - if you need it

PF=R/Z
=6/10
= 0.6

and a capacitor means it is leading

edit : apologies novice sparkus didn't see you had answered it on the next page - at least we agree lol

 

[JUD]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Im back with another .lets hope it doesnt continue at this rate as I have 140 practice questions.

ok

what is the kva of aload given that the true power is 100kW and the ractive power is 25 kVAr

options are

a. 175 kVA
b. 150 kVA
c. 200 kVA and
d. 125 KVA

the answers d (125 kVA) but surely you dont add the 25 kVAr to the 100 Kw and what with 100 added to 25 being 125 just stick a kVA on the end

I get 103kVA for this one.

kVA = √(kW² + kVAr²) = √(100² + 25²) = 103kVA

 

[pushrod]

Re: Cant remember studying this but if snyone can help me out that that would be swee

I get 103kVA for this one.

kVA = √(kW² + kVAr²) = √(100² + 25²) = 103kVA

Aaah the good old option E) !!

In actual fact it is D)



It is the typical trick typo question - the typist mistook a 7 for a 2! The reactive power is actually 75 kVAr!

I know this because for some reason the examiners have a fascination for 3, 4, 5 triangles - in this case 75, 100, 125 - why i don't know - maybe they don't own calculators.

 

[JUD]

Re: Cant remember studying this but if snyone can help me out that that would be swee

Aaah the good old option E) !!

In actual fact it is D)



It is the typical trick typo question - the typist mistook a 7 for a 2! The reactive power is actually 75 kVAr!

I know this because for some reason the examiners have a fascination for 3, 4, 5 triangles - in this case 75, 100, 125 - why i don't know - maybe they don't own calculators.

Of course. I should have known.

You have to correct the question before you answer it.

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

if anyone can help me to answer these id be greatfull as my exams in the morning

the power factor of a resistive and capacative circuit haveing an impedance of 3 ohms and a resistance of 2.5 ohms is

the answers 0.83 leading

 

[JUD]

Re: Cant remember studying this but if snyone can help me out that that would be swee

if anyone can help me to answer these id be greatfull as my exams in the morning

the power factor of a resistive and capacative circuit haveing an impedance of 3 ohms and a resistance of 2.5 ohms is

the answers 0.83 leading

pf = Resistance ÷ Impedance

2.5 ÷ 3 = 0.83 (leading because it's capacitive)

 

[Sintra]

Re: Cant remember studying this but if snyone can help me out that that would be swee

PF=R/Z

PF=2.5/3

PF = 0.83 leading as its capacitive

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

thanks alot guys

 

[lofty84]

Re: Cant remember studying this but if snyone can help me out that that would be swee

if anyone knows why the kva of a load is 125 Kva given that the true power is 100kW and the reactive power is 75Kvar that would be handy.