G
No nearly, but not quite.Can somebody have a look at this and tell me which tree I'm barking up?
Using the Adiabatic equation to determine the required size of main bonding and therefore the size of supplementary bonding.
Ze = 0.18
PFC = 1.3 kA
Fuse type 1361 IIa
S = square root (1300 x 1300 x 0.1) /115
= 3.57
Is that right? Seems like a very low value for main earth
Would any of you know if actually fitting a main earthing conductor on a TT or TN-S is notifiable or not?
Cheers
His wording isnt clear but he mentioned main earth at the bottom of his equation so his intention was selecting the size of bonding conductors in accordance with the calculated size of his earthing conductor.
Using the Adiabatic equation to determine the required size of main bonding and therefore the size of supplementary bonding.
Where does the 0.1s disconnection time come from at the top of the thread? Why not 5s?
Widdler is absolutely correct in what he stated, according to what the OP had posted!!The adiabatic equation is used for sizing of the earth conductor and protective conductors only, It's ''NOT'' to be used for bonding conductors.