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Hi,
I am currently studying to become an electrician and keep seeing this question (normally different values) and I am not sure how to work this out. Would someone be able to let me know how you work this out?
The measured value of loop impedance for a circuit is 2.4Ω. If the temperature at the time of the test was 20°C and the cable is 70°C (factor 1.2) what is the corrected value. Ze = 0.4Ω:
a) 2.88 Ω
b) 2.8 Ω
c) 2.4 Ω
d) 2.0 Ω
I am currently studying to become an electrician and keep seeing this question (normally different values) and I am not sure how to work this out. Would someone be able to let me know how you work this out?
The measured value of loop impedance for a circuit is 2.4Ω. If the temperature at the time of the test was 20°C and the cable is 70°C (factor 1.2) what is the corrected value. Ze = 0.4Ω:
a) 2.88 Ω
b) 2.8 Ω
c) 2.4 Ω
d) 2.0 Ω