Discuss 2392 Question in the Electrician Courses : Electrical Quals area at ElectriciansForums.net

Reaction score
29
A circuit has an external loop impedance Ze of 0.6. The maximum value of (R1 + R2), to BS7671:2008, on a circuit protected by a Type B 32A circuit breaker giving a 0.4 second disconnection time will be:

A: 1.44
B: 2.04
C: 0.84
D: 0.24

I got this wrong but have since worked it out I think.

To calculate Zs you need Ia

To get Ia you multiply breaker type by 5 in this case and get 160, confirmed on regs p301

then

Zs = Uo / Ia

Uo = Nominal Voltage = 230
Ia = Current causing the operation of the protective device within the specified time = 160A

So...

230 / 160 = 1.4375

Not quite so I guessed and minused the Ze of 0.6

1.4375 - 0.6 = 0.8375

I can't explain why if this is right?
 
Last edited:
Zsmax (1.44*0.8)for a given MCB (table 41.3) <= Ze (0.6) + R1+R2(0.55)
So 0.55 Ohm is the real answer

C&G answer is 1.44 <= 0.6 + 0.84

O.84 Ohms

This could be confusing since this answer makes no allowance for ambient and operating temperatures.
Also to get the answer it encourages you to use R1+R2 <= Zs -Ze which is not advisable because it may include, in reality, earth parallel paths.
 
It still confuses the hell out of me. To calculate the Zs for the circuit in question you would need to establish the Ia of the protective device.

How do you calculate Ia without a book giving you the max Zs for the circuit protective device?
 
Zs = Ze + (R1+R2)
Max Zs = Uo ÷ Ia
Max Measured Zs = (Uo ÷ Ia) x 0.8 (rule of thumb to correct for conductor operating temperature)

For BS 60898/61009 circuit breakers Ia is easy..

Type B = 5 x In
Type C = 10 x In
Type D = 20 x In

For other types of OCPD you use the time/current characteristics graphs in App 3 of BS 7671
 
I think JUD's answer is clearer than mine.

Go through it step by step until the 'penny drops'

All the info to do the calculation is there.

To calculate the max Zs, rather than using the tables you have type B = 5*In, type C= 10*In and Type D = 20*In for each type of MCB are rules of thumb given to you by BS7671.
 
as jud says. max. Zs is 230/ ( 5 x Ia ) = 230/160 = 1.44 ( for a 32A type B )
 

Reply to 2392 Question in the Electrician Courses : Electrical Quals area at ElectriciansForums.net

Similar Threads

Hi was wondering if im doing this right. The question in: Determine for a chosen circuit "the minimum possible csa of cpc which will satisfy the...
Replies
26
Views
4K
Hi Guy's, I'm revising for my 18th amd 2 and came across a question that has me a little confused. I think its probably the question is badly...
Replies
11
Views
1K
Hi everyone Recently I have come across an advert of someone selling Afdds C type and the person mentioned the need to sell because Zs was too...
Replies
16
Views
3K
I have been going round in circles with this question. I just cant seem to get an answer remotely close to the options. Continuity of a ring...
Replies
6
Views
1K
Hello everyone I'm Chris. I am taking the 2391 in February. This question is from the c&g main site under 2391 sample questions. Continuity of a...
Replies
3
Views
4K

OFFICIAL SPONSORS

Electrical Goods - Electrical Tools - Brand Names Electrician Courses Green Electrical Goods PCB Way Electrical Goods - Electrical Tools - Brand Names Pushfit Wire Connectors Electric Underfloor Heating Electrician Courses
These Official Forum Sponsors May Provide Discounts to Regular Forum Members - If you would like to sponsor us then CLICK HERE and post a thread with who you are, and we'll send you some stats etc
This website was designed, optimised and is hosted by Untold Media. Operating under the name Untold Media since 2001.
Back
Top
AdBlock Detected

We get it, advertisements are annoying!

Sure, ad-blocking software does a great job at blocking ads, but it also blocks useful features of our website. For the best site experience please disable your AdBlocker.

I've Disabled AdBlock