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A circuit has an external loop impedance Ze of 0.6. The maximum value of (R1 + R2), to BS7671:2008, on a circuit protected by a Type B 32A circuit breaker giving a 0.4 second disconnection time will be:
A: 1.44
B: 2.04
C: 0.84
D: 0.24
I got this wrong but have since worked it out I think.
To calculate Zs you need Ia
To get Ia you multiply breaker type by 5 in this case and get 160, confirmed on regs p301
then
Zs = Uo / Ia
Uo = Nominal Voltage = 230
Ia = Current causing the operation of the protective device within the specified time = 160A
So...
230 / 160 = 1.4375
Not quite so I guessed and minused the Ze of 0.6
1.4375 - 0.6 = 0.8375
I can't explain why if this is right?
A: 1.44
B: 2.04
C: 0.84
D: 0.24
I got this wrong but have since worked it out I think.
To calculate Zs you need Ia
To get Ia you multiply breaker type by 5 in this case and get 160, confirmed on regs p301
then
Zs = Uo / Ia
Uo = Nominal Voltage = 230
Ia = Current causing the operation of the protective device within the specified time = 160A
So...
230 / 160 = 1.4375
Not quite so I guessed and minused the Ze of 0.6
1.4375 - 0.6 = 0.8375
I can't explain why if this is right?
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