M

mh10acj

Hello everybody,
This is my first post names Micky. I was wondering if anyone could help me out with this question I’ve have been struggling with it for a long time. As a result I’ve lost a large part of my hair, mainly from the frontal region .

Question: - Given that the resistance per meter of 2.5mm^2 cable is 7.41MΩ/M at 20(degrees), what would the approximate R1 + R2 reading be at the extreme end of a 25(meter) long 20A radial socket outlet circuit

I would like to know step by step how this is worked out and what you have to do to get the answer.

Thanks in advance for any help or assistance
 
Ah yes I thought that looked strange - it might sound pedantic but you've put "7.41MΩ/M", but it's actually "7.41mΩ/m" as in milliohms, not megaohms. Appendix 9 of the onsite guide (page 166) gives you the resistance of R1+R2 per metre of copper conductors at 20°C.
All you do is select the right cable size (if it's T&E with the correct CPC) and multiply that by the length to give you the resistance at 20°C,
eg:
2.5mm² with 1mm² CPC is 25.51 mΩ/m
25.51 x 25m = 637.75mΩ, or 0.64Ω.
 
but who uses 2.5mm cable with 1.0mm cpc.
 
Well that was just an example, but if you like I'll demonstrate with 1.5mm² CPC:

2.5mm² with 1.5mm² CPC is 19.51 mΩ/m
19.51 x 25m = 487.75mΩ, or 0.49Ω.


BTW the first value given for each size cable is for R1 only, ie the line conductor with no CPC.
 
sometimes they just give theory questions for understanding and not for real onsite working

Yes but calculating R1+R2 is a rather important theory question wouldn't you say?

While testing, any suspect measured figure can be cross-checked against the approximate distance and cable type to reference the expected reading with the measured value.
 
Fair play for posting, but when these questions come up, I always find myself asking 'why don't you ask the lecturer?' Unless you're doing a distance learning course I suppose.
 
I agree that's what lecturers should be there for and if you have a good one they won't mind at all, but I understand it can be a bit daunting asking in front of the class or having things explained verbally, which is where t'internet comes into it's own.
 

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