S
sparkyork
hi got another countdown conundrum!!
if ive got a 12v dc supply in my van rated at 15a, and i connect in an invertor transforming this to 230v rated at 150w.
12v 15A = 230v .6A (150w/230)
i know as the volts go up the currents come down and vise versa, im trying to figure out the max wattage 230v supply i can have!!
is it a case of 230/12 = about 19.1, so 0.6A x 19.1 = 11.5A?
meaning that my existing 12v 15A supply is quite happy with this,
so if i wanted say 1000w 230v in me van!! would it be:-
1000/230 = 4.34A 4.34 x 19.1 = 82.8A?!
as you can gather im wanting mains in me van so i can charge drills etc as im driving to jobs etc, do my sums make sense?? i only want a true sine version as well, as i know modified sine can damage batterys/chargers.
seen on tinternet you can get 8KW invertors??
8000/230 = 34.7 34.7 X 19.1 = 662A! surely this must be with the engine running or what?????
if ive got a 12v dc supply in my van rated at 15a, and i connect in an invertor transforming this to 230v rated at 150w.
12v 15A = 230v .6A (150w/230)
i know as the volts go up the currents come down and vise versa, im trying to figure out the max wattage 230v supply i can have!!
is it a case of 230/12 = about 19.1, so 0.6A x 19.1 = 11.5A?
meaning that my existing 12v 15A supply is quite happy with this,
so if i wanted say 1000w 230v in me van!! would it be:-
1000/230 = 4.34A 4.34 x 19.1 = 82.8A?!
as you can gather im wanting mains in me van so i can charge drills etc as im driving to jobs etc, do my sums make sense?? i only want a true sine version as well, as i know modified sine can damage batterys/chargers.
seen on tinternet you can get 8KW invertors??
8000/230 = 34.7 34.7 X 19.1 = 662A! surely this must be with the engine running or what?????