Load and heat

[HandySparks]

You clearly don't understand ...

See post #37
BTW, I'm agreeing with you.

 

[The Ghost]

You clearly don't understand the very simple physics you learned at school then

What you say of course makes complete sense. My brain however is not quite getting it. What am I missing?

 

[telectrix]

take a load of 10kW @ 240V for example.

P=I V so I = P/V = 10,000/240 = 41.667A

from that using ohm's law, R = V/I = 5.76 ohms

now assume that V =230V

I =V/R, so I= 230/5.76 = 39.93A

so @ 230V P = VI = 9.184kW.

 

[DPG]

Thanks Tel for a more helpful reply than many have been. Daz

 

[telectrix]

there will be a very slight variation on that as with the slightly higher current @ 240V, the cable will be very slightly warmer, thus having a very slightly higher resistance, but the difference is too small to be considered.

 

[The Ghost]

Ok its 11755w 49.8a at 236v

 

[The Ghost]

Thanks Tel thats crystal clear, now I see exactly what you all mean.