Connect 25 AA batteries in parallel and series

[Malooq Omar Tariq]

Hello,

I have 25 batteries that are AA using 1.5 volts each, that is total = 37. 5 volts for 25 batteries. I want to know please the right way to wire all the batteries together to make a parallel and series battery pack. Please tell how to wire each battery together to connect all 25 AA batteries to make a parallel and series battery pack?

Thanks for your time and effort. Enjoy your day and have a good week. All the best for your successful future.

 

[mache]

What is your target voltage output you want from this pack??

 

[Malooq Omar Tariq]

What is your target voltage output you want from this pack??

Hello,

I just want to find out how to wire each battery together to connect all 25 batteries together in series and parallel. I want to test the total voltage when connecting AA batteries in series that are 1.5 volts is 37 volts using 100 light emitting diodes that are 5 volts each, that is 500 volts. Also, the total voltage when connecting AA batteries in parallel is 1.5 volts. I want to test how long the batteries can power 100 light emitting diodes and the total amp hours for 25 AA batteries is 55 amp hours. Link to battery test for amp hours here - Discharge tests of Alkaline AA batteries - http://www.powerstream.com/AA-tests.htm

 

[paul291277]

you wire them in parellel, you'll get 1.5V, you wire them in series you'll get 37.5V

 

[Des 56]

Connect so many batteries together in series is not a good idea

You seem to be resurrecting in earnest the term accumulator
As asked previously what voltage are you seeking

 

[Malooq Omar Tariq]

you wire them in parellel, you'll get 1.5V, you wire them in series you'll get 37.5V

Hello,

Thanks for checking that my workings out for parallel, that is 1.5 volts for 25 AA batteries, 2.20amp hours times 25 AA batteries is 55 amp hours and is correct. Thanks for checking that my working out for series, that is 1.5 volts times 25 AA batteries is 37.5 volts in total is right.

 

[Malooq Omar Tariq]

Connect so many batteries together in series is not a good idea

You seem to be resurrecting in earnest the term accumulator
As asked previously what voltage are you seeking

I do not want to have a specific voltage number to get from 25 AA batteries. I am using 25 AA batteries because the amount of electric, 37.5 volts is safer to work with than 220 volts that you have when using a power socket. All I want to do is from 25 AA batteries when connecting in series, that is 1.5 volts times 25 AA batteries = 37.5 volts.

25 AA batteries to power seven light emitting diodes out of 100 light emitting diodes
I am going to use 25 AA batteries to try to power as many light emitting diodes as 25 AA batteries able to. 25 AA batteries in series is 37. 5 volts. 25 AA batteries in series is 37.5 volts divide by 5 volts means 25 AA batteries are able to power 7 light emitting diodes out of 100 light emitting diodes. Each light emitting diode uses 5 volts, 5 volts times 100 light emitting diodes is 500 volts. When connecting in parallel, 1.5 volts is from 25 AA batteries, times 2.20 amp hours for 25 AA batteries and total amp hours is 55 amp hours.

Four 9 volt batteries able to light up seven light emitting diodes
I have four 9 volt batteries that is total of 36 volts. 36 volts divide by 5 is 7.2. 36 volts from four 9 volt batteries is able to power seven light emitting diodes. I want to be able to link up four 9 volt batteries in series and the 25 AA batteries in series, that is 73.5 volts.73.5 volts divide by 5 is able to power fourteen light emitting diodes. How do you link up four 9 volt batteries with 25 AA 1.5 volt batteries both in series?

Thanks for all your help. Have a nice day with your loving family and enjoy your week with your loving family and friends.

 

[Bob Geldoff1234]

Its a lot easier to use a transformer.Safe working voltage and huge savings on 25 batteries.Connecting 25 aa batteries is not cost effective.

 

[Malooq Omar Tariq]

Its a lot easier to use a transformer.Safe working voltage and huge savings on 25 batteries.Connecting 25 aa batteries is not cost effective.

Hello,

This just a little project, I do not want to use electric from mains such as 220 volts. It is a lot safer and easier to work with 73.5 volts when connecting 25 AA batteries in series and four 9 volt batteries in series together. Can anyone show how to connect 25 AA batteries in series and four 9 volt batteries in series together?

Thanks for all effort and time to help. Have a nice, happy day.

 

[FatAlan]

What are you trying make Malooq? Are you just experimenting with LEDs or are you trying to light something specific?

 

[Malooq Omar Tariq]

What are you trying make Malooq? Are you just experimenting with LEDs or are you trying to light something specific?

I have got to make using a solder iron lots of tiny holes that allow the light emitting diodes to stand on a sheet I cut out from a plastic box. Then, I glue all one hundred light emitting diodes onto the surface. Now, I am trying to power as many as I am able to with batteries. Can you show the way to wire and connect 25 aa batteries in series and four 9 volt batteries in series together?

Thanks for all your help. Enjoy your day and week. Have a good future.

 

[dmxtothemax]

you will never power 100 leds wired in series from this battery arrangement as the voltage is not high enough.
What you should consider is wiring the 100 leds in a series parrallel arrangement
to suit what ever voltage you decide to use, up to the maximum available of 37.5v.
What color leds are they ?
this will tell us the voltage !

 

[Malooq Omar Tariq]

you will never power 100 leds wired in series from this battery arrangement as the voltage is not high enough.
What you should consider is wiring the 100 leds in a series parrallel arrangement
to suit what ever voltage you decide to use, up to the maximum available of 37.5v.
What color leds are they ?
this will tell us the voltage !

Hello,

The 100 light emitting diodes are white and have 5 volts for one light emitting diode making 100 light emitting diodes a total of 500 volts. How do you put the 100 light emitting diodes in series or parallel?

Thanks for all your help. Enjoy your happy days and weeks.

 

[telectrix]

i'd say this idea was akin to Sierra leone's idea of a space rocket... a non-starter.

 

[Malooq Omar Tariq]

Working out resistor for 100 white light emitting diodes
5 volt white light emitting diode with 60 milliamp. 5 volt light emitting diode times 100 light emitting diodes is 500 volts. 100 light emitting diodes times 60 milliamps is 6,000 milliamps hours. Ampere equation is Ah = mAh /1000. To find out Ampere hours, 6,000 milliamp hours divide by 1,000 is 6 ampere.

Ohms law is V for voltage, I for current in amps and R for resistance in ohms. I use the Ohms law equation that is V = I . R.

Work out voltage, equation is V = I times R
V is volts, I is for ampere, 6 ampere times 84 ohms = 504 volts.

Work out current in ampere, equation is I = V divide by R
I is current in ampere, 504 volts divide by 84 ohms = 6 ampere.

Work out resistance, equation is R = V divide by I
R is resistance, volts 504 divide by 6 ampere = 84 ohms

Work out power, equation is P = V times I
P is for power, Volts is 504 times 6 ampere is 3,024 watts

Please check that all calculations are right? Please tell way to buy the right resistor, that is 84 ohm resistor that handles 504 volts for 100 light emitting diodes?

Thanks for all your help. Have a good week with your loving family and friends.

 

[Malooq Omar Tariq]

To find out 6 ampere into milliamps, one ampere is equal to 1,00 milliamp, equation is mAh = Ah times 1000. 6 ampere to milliamps is 6 ampere times 1000 = 6,000 milliampere hours.

 

[Malooq Omar Tariq]

To work out energy, power = Energy divide by time. One watt is one joules. 3024 watts to joules is 3024 joules. Power = 3024 joules divide by 24 hours. 60 seconds in minute. 60 minutes is one hour times 60 seconds = 3,600 seconds. 24 hours is 60 minutes times 1,440 minutes. 1,440 minutes for 24 hours times 60 is 86,400 seconds. Power = 3024 joules divide by 86,400 seconds = 0.035 watts.

 

[Malooq Omar Tariq]

Power of one light emitting diode is 5 volts and 60 milliamp in watts. Ampere equation is Ah = mAh /1000.. 60 milliamp / 1000 = 0.06 milliamp. Power is I current in ampere and Voltage. Voltage 5 times 0.06 ampere = 0.30 watts for one light emitting diode. To work out current for fuse, current = power in watts divide by voltage. Power in watts is 3024 divide by 500 volts is 6.048, thus need to have 13 amp fuse.

 

[Malooq Omar Tariq]

To work out cost to run 100 light emitting diodes, you divide watts by 1000 to get kilowatt hour. 3024 watts total for one hundred light emitting diodes divide by 1,000 is 3.024. 24 hours is 86,400 seconds. Turn the 86,400 seconds into hours you divide by 3,600, that is seconds in one hour, total is 24 hours,

To work out cost for electric, you use power in kilowatt, 3.024 times time in hours, 24 x cost of one kilowatt, 11.871 from Gas & electricity prices per kWh - UKPower.co.uk - https://www.ukpower.co.uk/home_energy/tariffs-per-unit-kwh = 861.549696 in pence. 861.549696 into pounds is 861.549696 / 100 pence in one pound = £8.61 pence.

 

[Paul228]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.
Are you building a 100 LED light board and seeing if it's cheaper to run of batteries or stepped down mains?
Or are you looking to find the cheapest way to light your property?

 

[Malooq Omar Tariq]

£1.00 for twenty double aa batteries times 1.5 volts that is thirty volts. £10.00 is 200 aa batteries. 200 aa batteries times 1.5 volts is 300 volts. £5.00 times 20 aa batteries is 100 volts. £20.00 times 20 aa batteries = 400 aa batteries. 400 aa batteries times 1.5 volts = 600 volts.

600 volts into watts is P is power for watts = Volts 600 times I current in amps, 6 = 3,600 watts. To get watts into kilowatt hours, 3,600 divide by 1000 = 3.6 killowatts. 86,400 seconds in 24 hours, divide by 3,600 seconds in one hour, is 24 hours. Total cost is power in kilowatts, 3.6 killowatts x time in hours, 24 x £20.00 batteries = 1728 pence. 1728 pence, /100, 100 pence in £1.00 = £17.28

 

[Malooq Omar Tariq]

£20.00 Battery cost per kilowatt
£20.00 for 600 volts and 400 aa batteries. 600 volts times 2.20 amps = 1,320 watts. To get watts into kilowatt hours, 1,320 divide by 1000 = 1.32 killowatts. £20.00 divide by 1.32 kilowatts = 15.1515151515. £15.15 pence per 1 kilowatt, that is 1000 watts. 1320 watts times 2.20 amps is 600 volts.

 

[Malooq Omar Tariq]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.
Are you building a 100 LED light board and seeing if it's cheaper to run of batteries or stepped down mains?
Or are you looking to find the cheapest way to light your property?

I know that electric at 11.871 pence per kilowatt is £8.61 for 24 hours. Then, battery costs £17.28 for 24 hours. Electric for 24 hours, £8.61 - £17.28 for 24 hours from battery makes electric £8.67 cheaper. How do I buy a resistor that is 84 ohms and can handle 600 watts? Thanks for all your help. Enjoy your good week with your loving family and friends.

 

[Paul228]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

 

[Bob Geldoff1234]

As they say on Dragons Den....I'm out....

 

[Paul228]

Tell me why I don't like Mondays Mr geldoff

 

[Malooq Omar Tariq]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

I am not going to use electric power from electric power plug. I am going to use batteries, 400 aa batteries for £20.00 means 600 volts. To work out watts, 6 ampere times 600 is 3,600 watts. 500 volts for light emitting diodes times 6 ampere is 3,000 watt. 100 volts over and 600 watts over. Work out resistance, equation is R = V divide by I. R is resistance, volts 600 divide by 6 ampere = 100 ohms
Work out current in ampere, equation is I = V divide by R. I is current in ampere, 600 volts divide by 100 ohms = 6 ampere. How can I find a resistor that is 100 ohms and can handle 600 volts please?

Thanks for all your help. Enjoy your happy week and day with your loving family and friends.

 

[Paul228]

Why.
Just use less batteries or instead of wiring all 100 LEDS in series, try doing a combination of series and parallel wiring.
Take a look at this
LED circuit - Wikipedia - https://en.m.wikipedia.org/wiki/LED_circuit

 

[dmxtothemax]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

 

[Malooq Omar Tariq]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

Panasonic Eneloop AA pack 8 that have 1900 milliamp hours capacity. Total milliamp hours for 100 light emitting diodes in parallel is 6,000 milliamp hours because 60 milliamp for one light emitting diode times 100 is 6,000 milliamp hours.

Do you think that is better way for more energy in batteries that last a lot longer than alkaline aa batteries that run out of energy after a few uses?

Time that eight panasonic eneloop aa batteries power one hundred light emitting diodes

Eight Panasonic Eneloop AA batteries at 1.20 volts is 17,100 milliamp hours. 17,100 milliamp into amp is 17,100 milliamp divide by 1000 milliamp that is one amp is 17.1 amp hour from eight aa panasonic eneloop batteries. 6,000 milliamp from 100 light emitting diodes divide by 1000 milliamp that is one amp is 6 ampere. 8 AA batteries at 1900 milliamp hours are 17.1 ampere then divide by 6 ampere, that is one hundred emitting diodes means batteries last for 2.85, that is 2 hours and 0.85 times 60 minutes is 51 minutes. Panasonic Eneloop AA batteries cost £11.99 saving £8.01 in comparison to £20.00 worth of AA batteries that make 600 volts.

 

[Besoeker]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.

I agree. A succinct and clear description of the project would be a great help. Is it for a Christmas tree, a fish tank, or a pot growing operation? Or all of the above?

 

[Malooq Omar Tariq]

I agree. A succinct and clear description of the project would be a great help. Is it for a Christmas tree, a fish tank, or a pot growing operation? Or all of the above?

It is for anything that I can use light for: for reading books, for taking washing off, for a bike ride, for use as a torch, for decorations on a christmas tree or christmas lights, to grow food indoors and much more.

 

[Taylortwocities]

I cannot be bothered to wade through all of the foregoing as I kind of think i know about Ohms law etc. But, from a practical standpoint, in my view you will be spending most of your free time changing expired batteries.
Dont forget that batteries deplete at different rates, How will you discover which ones need changing, or will you change a hundred batteries at a time?

 

[telectrix]

seems to me a bit like shovelling the ---- out of a cowshed with a teaspoon.

 

[Des 56]

There surely has to be a David Cockburn book on this very subject out there somewhere

 

[Malooq Omar Tariq]

I cannot be bothered to wade through all of the foregoing as I kind of think i know about Ohms law etc. But, from a practical standpoint, in my view you will be spending most of your free time changing expired batteries.
Dont forget that batteries deplete at different rates, How will you discover which ones need changing, or will you change a hundred batteries at a time?

This is why I decide to choose this battery instead, Eight Panasonic Eneloop AA batteries at 1.20 volts gives 15,200 milliamp hours. The Panasonic Eneloop AA batteries are rechargeable up to 2,100 times. 1900 milliamps on single charge times 2,100 is about 3,99,0000 milliamps hours. 3990000 milliamp hours divide by 6000 milliamp hours for one hundred light emitting diodes is 665 hours. The Panasonic Eneloop from 1900 milliamp in five years keeps 70% capacity, that means 0.70% times 1900 milliamp is 1330 milliamps in five years and loses 570 milliamps in five years time.

Update on right milliamps and hours for running one hundred light emitting diodes for the batteries. The batteries in parallel when 15,200 milliamp into amp is 15,200 milliamp divide by 1000 milliamp that is one amp is 15.2 amp hour from eight aa panasonic eneloop batteries. 6,000 milliamp from 100 light emitting diodes divide by 1000 milliamp that is one amp is 6 ampere. 8 AA batteries at 1900 milliamp hours are 15.2 ampere then divide by 6 ampere, that is one hundred emitting diodes means batteries last for 15.2, that is 2 hours and 0.53 times 60 minutes is 31.8 minutes. Panasonic Eneloop AA batteries cost £11.99 saving £8.01 in comparison to £20.00 worth of AA batteries that make 600 volts.

 

[telectrix]

.............

 

[Specialist]

@Malooq Omar Tariq : You say that a particular battery loses 30% in five years. You do realise that, this will relate to loss of charge while sitting idle on the shelf ?.
It doesn't mean it will lose 30% over 5 years when under load.
You keep throwing up the same nonsensical figures in post after post, why ?. All this has served to do is waste the time of people that attempted to help you and alienate them.

 

[Specialist]

.............

View attachment 36589

DITTO.

 

[Rpa07]

Very polite chap, I'll give him that!

 

[Specialist]

Very polite chap, I'll give him that!

Exceptionally, but wasting time & getting nowhere. He asked for advice & to be fair the guys have tried hard to give it.
All they get back is the same thing repeated, calculations that look like they've just been pulled straight from the pages of a text book.

 

[Paul228]

Pop to a diy shop, buy a ready built LED torch, they cost about £3 and only take 3aa batteries'. Mines been used daily and still has the same batteries 6 months on.

 

[Specialist]

Pop to a diy shop, buy a ready built LED torch, they cost about £3 and only take 3aa batteries'. Mines been used daily and still has the same batteries 6 months on.

? ? ?

 

[punkin]

This Malooq guy is taking the ---- with you all, if you truly are not taking the ---- Malooq then you shouldn't be connecting the LED's because you don't understand what you are doing or talking about.

 

[CACJL]

Hello,

I have 25 batteries that are AA using 1.5 volts each, that is total = 37. 5 volts for 25 batteries. I want to know please the right way to wire all the batteries together to make a parallel and series battery pack. Please tell how to wire each battery together to connect all 25 AA batteries to make a parallel and series battery pack?

Thanks for your time and effort. Enjoy your day and have a good week. All the best for your successful future.

Hello,

I have 25 batteries that are AA using 1.5 volts each, that is total = 37. 5 volts for 25 batteries. I want to know please the right way to wire all the batteries together to make a parallel and series battery pack. Please tell how to wire each battery together to connect all 25 AA batteries to make a parallel and series battery pack?

Thanks for your time and effort. Enjoy your day and have a good week. All the best for your successful future.

 

[CACJL]

I would need see a data sheet on the LEDs, the manufactures name and the type number of the LEDs. Then I could you a complete answer. Ultra low voltage were the regulations do not apply is 30 volts dc and 24 volts ac.

 

[Malooq Omar Tariq]

Hello,

I understand now by learning the way to connect light emitting diodes in parallel and series. I understand through reading the way to connect resistors in series or parallel as well. This is my last post here because I am finishing this thread as I understand the way circuits, resistors, series and parrllel circuits work.

Please forum moderators close this thread. I thank you moderators for your help.

Thanks for everyones help that helps myself to understand the way to make light emitting diodes work in different circuits. Thanks for all your time, effort to help myself and many others that read here.

I hope you all are well and I want you to have every success in life. Enjoy your good day, happy week with your loving family and friends. All the best for your future.

 

[M-Ty]

Hello,

I understand now by learning the way to connect light emitting diodes in parallel and series. I understand through reading the way to connect resistors in series or parallel as well. This is my last post here because I am finishing this thread as I understand the way circuits, resistors, series and parrllel circuits work.

Please forum moderators close this thread. I thank you moderators for your help.

Thanks for everyones help that helps myself to understand the way to make light emitting diodes work in different circuits. Thanks for all your time, effort to help myself and many others that read here.

I hope you all are well and I want you to have every success in life. Enjoy your good day, happy week with your loving family and friends. All the best for your future.

 

[M-Ty]

I would be interested to see your solutions.

 

[w0z]

It is neither recommended nor good electronics practice to connect AA batteries in parallel, if one cell goes low resistance it will drain the others (unless you use a diode on the output of each cell which in the case of AA's isn't practical as the forward voltage drop on the diode will be too significant). AA's also vary from cell to cell, nominally 1.5V alkaline but I've had new ones measure nearly 1.7V. NiMh cells measure 1.2V. (Don't even think about lithium, the cost would be huge)

LEDs work at constant device current for optimum output and the resistance in series with the led or leds is calculated to supply the maximum (or near maximum) current at the highest voltage the power source can provide, after taking into account the LED voltage drop. (or you could use an led driver chip).

You would also need to add in the cost of battery holders, unless he's going to try to solder all the cells together (surely not!).

As an example, a 1.2V nimh cell at say 1500mAh, not taking into account any losses, would provide 1.2x1.5=1.8Wh- you'd need 555 cells to provide 1 kWh, at a quid each that would cost £555. (not that there's anything relevant about a kWh other than it costs about 13 pence from your local electricity supplier)