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Can someone explain why fault current is higher when your zs is lower trying to write down reason but struggling on what to put
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Ohms law. Remember the old VIR triangle.
Diib I now that lol just been working out thermal constraints on my design protect and noticing the lower the zs the higher the fault current was wondering if anyone could explain why other than ohms law
So if are zs are to good ie a very low impedance surely are high fault current could possibly be dangerous
So if are zs are to good ie a very low impedance surely are high fault current could possibly be dangerous
But with very low external impedance, comes rather large fault currents which may cause a few problems with your earthing conductor and the breaking capacity of your ocpd's
That's because the pages are probably stuck together Archie :lol:in one of the mags, can't find it now.
Really, I think you'll find the general B type breakers are 6kA, although with back up protection of your main fuse you'll get away with up to 16kA
Well all the MG ones we use are rated for 10kA anyways
Granted there are 6Ka out there to
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