OP
Moses
I have been having a quite night but after trying to get my mind round this I think it's time to reach for a bottle.
The way I understood this phenomenon was simple physics:
A is a measure of the number of electrons passing a point per second.
V is the potential difference so the force pushing the electrons along.
In plumbing speak the A is the volume of water and V is the pressure or head.
In a circuit the electrons will take the easiest route to ground. The electrons are all being squeezed through a small section of copper and therefore encounter resistance - V=I R. The back up due to resistance is the V measured between E and N. It is 0 at the consumer unit as this is near where E and N are merged tnc (not tt) so there is no relief of V by shorting N and E.
This leaves vd. Is this not caused by the resistance in the cable v=ir. E.g. If 10a of current flows through cable with 1 ohm of resistance the vd is 10v?
I am now going to pour a stiff one. Would be grateful for some clarity on this.
Physics????
A lot of mumbo Jumbo if you ask me!!!!!!
Iv'e never seen any electrons or even been shown any at the college.
Its not electrons, its positrons that flow when a current flows.