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Your generator is actually two generators. One outputs 230V ac and 850Watts and the other 14V dc at 20A which is 12 x 20 = 240Watts. The maximum power out of the 230V scoket is 850 Watts. The maximum power out of both 12V terminals is 240W (ie 100W from ones on left and 140W from one on right). Total ac and dc power is 850 + 240 = 1090W.
The generator struggles to power two olive machines because their combined power requirement is more than the 12V generator can provide, so they slow down the generator a bit which reduces its voltage output which reduces the power consumed by the olive machines motors which reduces the current flowing between the generator and the olive machines until the ability of the generator to supply power - its lower output voltage times the current is equal to that consumed by the olive machines. In electrical engineering this is called droop - the lowering of output voltage with increasing load for a generator, and the lowering of output power of a motor as its input voltage reduces. If possible the motor and generator interact through their individual droop characteristics to find a point of equilibrium where torque times speed of the generator = torque times speed of olive motor.
With regards to the length of cable - it takes energy to move electricity along wires and this energy appears as heat - the wires warm up. So if you put int X amount of energy at the supply end of the wire you will only be able to use X-Y at the load end were Y is the heat loss I just mentioned. To keep the the heat loss small the wires should be short and thick. This is especially important at low voltages such as 12V because it takes larger currents to move energy than at a higher voltage. eg: 12Volts x 10Amps -= 120Watts could be moved by 120Volts at 1 Amp since 120 x 1 = 120W.
The amount of heat loss depend not on the current but the current x the current. So in my example, the heat loss depends on 10 x 10 = 100 not 1 x 1 = 1 which means the heat loss in the connecting cable at the lower voltage of 12V is 100 times greater than at 120 V.
Wires have a property called resistance R which is a measure of how difficult it is for electricity to flow. Short thick wires have less resistance than long thin ones. The power lost in a wire is the current(I) x the current x the resistance IsquaredR = I x I x R.
The generator struggles to power two olive machines because their combined power requirement is more than the 12V generator can provide, so they slow down the generator a bit which reduces its voltage output which reduces the power consumed by the olive machines motors which reduces the current flowing between the generator and the olive machines until the ability of the generator to supply power - its lower output voltage times the current is equal to that consumed by the olive machines. In electrical engineering this is called droop - the lowering of output voltage with increasing load for a generator, and the lowering of output power of a motor as its input voltage reduces. If possible the motor and generator interact through their individual droop characteristics to find a point of equilibrium where torque times speed of the generator = torque times speed of olive motor.
With regards to the length of cable - it takes energy to move electricity along wires and this energy appears as heat - the wires warm up. So if you put int X amount of energy at the supply end of the wire you will only be able to use X-Y at the load end were Y is the heat loss I just mentioned. To keep the the heat loss small the wires should be short and thick. This is especially important at low voltages such as 12V because it takes larger currents to move energy than at a higher voltage. eg: 12Volts x 10Amps -= 120Watts could be moved by 120Volts at 1 Amp since 120 x 1 = 120W.
The amount of heat loss depend not on the current but the current x the current. So in my example, the heat loss depends on 10 x 10 = 100 not 1 x 1 = 1 which means the heat loss in the connecting cable at the lower voltage of 12V is 100 times greater than at 120 V.
Wires have a property called resistance R which is a measure of how difficult it is for electricity to flow. Short thick wires have less resistance than long thin ones. The power lost in a wire is the current(I) x the current x the resistance IsquaredR = I x I x R.
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