K
Kyran
Hello people Just so i get this right i thought i would post my maths here for people to comment on.
Garden lights on a sub main. Sub main is 20meters from the main CU on a 6mm armoured cable. the last light is 50 meters from the sub main. meaning end to end 70 odd meters.
So my maths are right yes?
cable to sub main
6mm = 7.3 mv/a/m on a 20 amp breaker, so
7.3 x 20 x 20 = 2.92v
cable from sub main to last light.
4mm = 11 mv/a/m on a 6 amp braker (4 core armoured, for two sets, switches of lights)
11 x 6 x 50 = 3.3
Add to to together and you end up with 6.22v drop at the end of 70 meters of cable. which is just in side the 6.9v allowed.
Sound good.
NEXT QUESTION unless i am being proper think.
How would you wire the switching as just released that that 70meters does not account for the switch lines. which would mean getting even larger CSA if not just for the sub main supply.
ops almost buggered it up.
Garden lights on a sub main. Sub main is 20meters from the main CU on a 6mm armoured cable. the last light is 50 meters from the sub main. meaning end to end 70 odd meters.
So my maths are right yes?
cable to sub main
6mm = 7.3 mv/a/m on a 20 amp breaker, so
7.3 x 20 x 20 = 2.92v
cable from sub main to last light.
4mm = 11 mv/a/m on a 6 amp braker (4 core armoured, for two sets, switches of lights)
11 x 6 x 50 = 3.3
Add to to together and you end up with 6.22v drop at the end of 70 meters of cable. which is just in side the 6.9v allowed.
Sound good.
NEXT QUESTION unless i am being proper think.
How would you wire the switching as just released that that 70meters does not account for the switch lines. which would mean getting even larger CSA if not just for the sub main supply.
ops almost buggered it up.