J

jamesBoater

i am just a little unsure if i need to use 5 seconds as my D/T or 0.4? PFC obtained through Ze test at origin.

i have been told 2 different answers and any guidance would be helpful.

thanks james
 
On TN systems the maximum permissable disconnection times are 0.4s for final circuits up to and including 32A. 5s for distribution circuits and final circuits over 32A.

For TT systems it is 0.2s and 1s respectively.

If you are trying to work out the 't' in an adiabatic equation then you should be using manufacturers data or at worst the regs book and the time current graphs to tell you what the D/T will be for the OCPD when exposed to the PEFC you have measured. Using 0.4 or 5s for your calculations will more often than not give you an earthing conductor size which is far higher than required.
 
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as above ^^^^^^ .
 
You need to work out the 'S' in the adiabatic for the size of your conductor, not t, you cant work out the 't' as this is determined by the maximum disconnection time allowed for the particular circuit, 0.1, 0.4 etc etc and is a constant.
 
The bit i was not sure about is what the max DT is. My PFC is taken at the origin through a Ze test. would this be a distribution circuit and be 5 seconds?

thanks james
 
no. t is the time the ocpd takes to trip with the pfc that you have measured. usually be 0.1sec. taken from appendix3 BGB. time/current curves.
 
its the fault current squared X the disconnection time (0.4 or 5 sec)...apply the square route to that sum then divide the result by the factor of K....which for copper is 115
 
its the fault current squared X the disconnection time (0.4 or 5 sec)...apply the square route to that sum then divide the result by the factor of K....which for copper is 115
. nope, glenn. get the value of t from time/current curves, and k is 143 if it's a single cable like as wot a main earth is.
 
. nope, glenn. get the value of t from time/current curves, and k is 143 if it's a single cable like as wot a main earth is.
i`l have a look at that ...
i`m going by what i was taught at college....

- - - Updated - - -

anyway Tel...i`ll send you that thing in a mo...
 
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k is 115 in a multicore cable or cables bunched, but it's 143 for a single cable in free air or clipped etc., as it has better cooling.
 
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Telex and D are right here. You have to work out using the graphs/manufacture data, the actual time in which it takes the over current protective device to disconnect the current that would flow in the circuit during fault conditions. (PFC) so if the pfc was lower it would take longer to disconnect! And vice versa! Hope this helps!!
 
Telex and D are right here. You have to work out using the graphs/manufacture data, the actual time in which it takes the over current protective device to disconnect the current that would flow in the circuit during fault conditions. (PFC) so if the pfc was lower it would take longer to disconnect! And vice versa! Hope this helps!!
i`m aware of disconnection times....
 
You could just refer to table 54.7 of the regs book, where the sizing of the earth has been calculated for you I believe?
 
You could if you wanted an easy life, but then you'd be oversizing the earthing conductor on 90% of the circuits you install. Each to their own.
 
You could just refer to table 54.7 of the regs book, where the sizing of the earth has been calculated for you I believe?
the adiabatic is good for calculating CPC/earth size for singles.....and also to make sure that any CPC within a cable is good for the time/current curves for the particular choice & setting of OPD being utilised...
say you had a ring final where the live conductors were intact but the CPC was broken....however all points served had R2....this is when the adiabatic would come in handy....it would confirm the difference between a pass and a fail.....
 
Okay I see, because basically the c.s.a has halved but still able to carry the fault current without any damage occurring?
 

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calculating main earth size
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